A 500 word composition based on pictures in unit 2 of Volume 2 of grade 5

A 500 word composition based on pictures in unit 2 of Volume 2 of grade 5


On a sunny and dark afternoon of a small football match, a group of boys happily walked to the open space and piled their bags and hats into two piles. The fierce match began. The golden haired goalkeeper's face turned white because of tension and happiness. Although his knee was scratched yesterday, he was not there at all



Sixth grade volume two look at the picture to write a fake illiterate composition, 400 to 500 words





A little football match


On a sunny afternoon, a group of boys happily went to the open space and threw their bags and hats into two piles, which became a simple goal. The fierce match began. The golden haired goalkeeper's face turned red because of tension and joy. Although his knee was scratched yesterday, he didn't care



What is the sum of the reciprocal of 3 / 5 plus the quotient of 1 / 4 divided by 3


The reciprocal of 3 / 5 is 5 / 3
The quotient of (1 / 4) / 3 is 1 / 12
So the sum is 5 / 3 + 1 / 12 = 21 / 12 = 7 / 4



X ⊕ y = 6x + 5Y, X ⊕ y = 3xy, we know (2 ⊕ 3) △ a = 324 to find a


(2⊕3)=6×2+5×3=27
27△a=3×27×a=81a=324
So, a = 4



Given the logarithm of X, find x lgx = LGA + LGB, logax = logam Logan


lgx=lga+lgb
lgx=lgab
x=ab
2、loga x=loga m/n
x=m/n



Given the function y = ax ^ 2-ax-4 (x ∈ R), if the function range y ≤ 0, then the value of a is
Ask for 3 hours to answer
There seems to be a specific answer, not a scope


Obviously, it doesn't hold when a = 0
If a > 0, the opening of the function is upward, X ∈ R, there must be a value greater than 0
When a



It is known that the vertex coordinates of the parabola are (2, - 3) and pass through points (1, - 52). (1) find the analytic expression of the function of the parabola and make the general picture of the function; (2) when x is in what range, y increases with the increase of X? When x is in what range, y decreases with the increase of X?


(1) Let y = a (X-2) 2-3 and substitute x = 1 and y = - 52 into - 52 = A-3, that is, a = 12, then the analytical formula of parabola is y = 12x2-2x-1; (2) when x > 2, y increases with the increase of X; when x < 2, y decreases with the increase of X



1.. X: 12 = 4 and 4 / 3:7 and 1 / 8 2.. 6 and 2 / 1: x = 6 and 6 / 5:4.1
3.. 0.6: x = 3 / 4:1 / 4
=


1、x=8
2、x=3.9
3、x=1/5



Make the numerator and denominator of the fraction not contain negative sign (1) - (y) / (- x) (2) (- X-Y) / x + 2Y (3) - (- 2Y) / (- 3x)


1.
y/x
two
-((x + y) / (x + 2Y)), the minus sign is written in front of the bar
three
-(2Y / 3x), the minus sign is written in front of the bar