Chinese book of Jiangsu Education Press primary school grade 6 Volume 1 unit 6 exercise 6 composition 400 words Writing about celebrities

Chinese book of Jiangsu Education Press primary school grade 6 Volume 1 unit 6 exercise 6 composition 400 words Writing about celebrities

Su Jiaoban sixth grade Chinese volume I exercise 4, exercise 5, exercise 6 composition
To write their own or different from other online

The calculation is as simple as possible

55×102
=55*(100+2)
=55*100+55*2
=5500+110
=5610

It is known that the tangent line of circle C: x ^ 2 + y ^ 2-2x-2y + 1 = 0 intersects x-axis, Y-axis lies at two points a and B, | OA | = a, | ob | = B, (a > 2, b > 2)
Verification: (A-2) * (b-2) = 2
Find the trajectory equation of the midpoint of line ab,
Find the minimum AOB area of triangle

Curve C is circle: (x-1) ^ 2 + (Y-1) ^ 2 = 1. Center of circle C (1,1), radius = 1, straight line L: X / A + Y / b = 1, if the straight line L is tangent to the circle, then: distance from C (1,1) to the straight line L = radius = | 1 / A + 1 / B - 1 | / radical (1 / A ^ 2 + 1 / b ^ 2) = = = > AB (ab-2a-2b-2) = 0 = = > ab-2a-2b + 2 = 0 = = > (A-2) (b-2) = 2

5X-3*5/21=5/7 0.36*5-3/4X=3/5 2/3(X+4.5)=7
The simple calculation is 2.42 △ 3 / 4 + 4.58 × 1 and 1 / 3-4 / 3 14.8 × 6.3-6.3 × 6.5 + 8.3 × 3.7
It's a simple problem, not an equation problem

First, the original formula is 2.42 × 4 / 3 + 4.58 × 4 / 3-4 / 3 = 4 / 3 (2.42 + 4.58-1) = 4 / 3 × 6 = 8
Second, the original formula = 6.3 × (14.8-6.3) + 8.3 × 3.7 = 53.55 + 30.71 = 84.26

It is known that a and B belong to R, α and β are the two imaginary roots of the equation x & sup2; + 2aX + B = 0, α / β + β / α = 1 | α - β | = 2 to find the real numbers a and B

There is a problem in this problem. Let's see if there is a problem in my derivation: from α / β + β / α = 1, we can get α ^ 2 + β ^ 2 = α β. From | α - β | = 2, we can get (α - β) ^ 2 = 4, that is, α ^ 2 + β ^ 2 - 2, α β = 4. From the above two formulas, we can get α ^ 2 + β ^ 2 = - 4, α β = - 4

(98 plus 147) divided by 49 = what's a simple calculation

Simple calculation method 98 / 49 = 2 147 / 49 = 3 2 + 3 = 5

The solution of the system of equations {ax + by = ab {2ax-3by = 12ab} about XY

2ax+2by=2ab （1）
2ax-3by=12ab （2）
(1) - (2) get
5by=-10ab
So by = - 2Ab, substitute (1) to get
ax=3ab
I wonder if there are other conditions for a and B, such as not equal to zero?

(0.125) ^ 5 * 2 ^ 18 (simple calculation)

（0.125）^5*2^18
=（0.125）^5*8^5 *8
=（0.125*8）^5*8
=1*8
=8

Let the solution set of proposition p: inequality ax ^ 2 + ax + 1 > 0 be r; proposition q: function f (x) = - (7-3a) ^ x is a decreasing function,
If only one of P and Q is true, find the value range of real number a

1) Suppose P is true and Q is false, then for proposition 1, a = 0 or a > 0 and a ^ 2-4a = 1
Suppose that 1 gives 0