If a is a rational number, then the sum of - A and | a | is () A may be plural B is not plural C can only be positive D can only be 0 E is not a positive number F can't be sure

If a is a rational number, then the sum of - A and | a | is () A may be plural B is not plural C can only be positive D can only be 0 E is not a positive number F can't be sure

Reward points: 20 - 14 days and 23 hours to the end of the problem
If a is a rational number, then the sum of - A and | a | is ()
A may be plural
B is not plural
C can only be positive
D can only be 0
E is not a positive number
F can't be sure
If you don't include real numbers, choose B, if you include F

Given f (2x-1) = 4x & # 178; - 4x, find f (x + 1)

f(2x-1）=4x²-4x
Let y = 2x-1, then x = (y + 1) / 2;
f(2x-1）= f(y) = 4x²-4x = 4x*(x-1) = 4*(y+1)/2*((y+1)/2-1) = 2(y+1)(y-1)/2=y^2-1
So f (x) = x ^ 2-1; f (x + 1) = (x + 1) ^ 2-1 = x ^ 2 + 2x

In the parallelogram ABCD, the bisector AE of ∠ a intersects CD at points e, ab = 10, BC = 6. Find the length of CE

Because DC / / AB, so the angle DAE = angle DEA, so de = ad = BC = 6,
So CE = 10-6 = 4

Two digit by one digit problem in Grade Four

40.2x11=221.2x12=242.2x13=263.2x14=284.2x15=305.2x16=326.2x17=347.2x18=368.2x19=389.2x20=4010.2x21=4211.2x22=4412.2x23=4613.2x24=4814.2x25=5015.2x26=5216.2x27=5417.2x28=5618.2x29=5819.2x30=6020.2x31=6...

In the cube abcd-a'b'c'd ', if e is the midpoint of edge AB, what is the tangent of the angle between the straight line c'e and the plane acc'a'?

The apostrophe of your superscript is replaced by a1b1c1d1. Analysis: take the midpoint F of AD, intersect AC at point m, and connect MC, then ∠ ec1m is the angle formed by the straight line C1E and plane acc1a1. By solving the triangle ec1m, the tangent value of the angle formed by the straight line C1E and plane acc1a1 can be obtained

If A2 + 4A + 1 = 0, and a4-ma2 + 1 / 2A3 + ma2 = 2A + 3

Are you sure the title is right? A4-ma2 + 1 / 2A3 + ma2 = 2A + 3
-Aren't the terms ma2 and + ma2 allowed to be deleted?
Maybe - Ma3

It is known that a (- 2,3), B (3,1) and P are on the x-axis. If the length of PA + Pb is the smallest, then the minimum is___ If the length of pa-pb is the largest, the maximum value is___ ．

(1) Find the minimum value: as shown in the figure: make the symmetric point B 'of point B about the X axis, connect ab', intersect the X axis at the point P, ∵ B and B 'symmetries, ∵ Pb = Pb ′, ∵ AP + BP = PA + B' P. according to the shortest line segment between the two points, we can know that point P is obtained. ∵ given that a (- 2,3), B (3,1), ∵ B 'coordinates are (3, - 1), we can get the length of the shortest distance ab', ab '= (3 + 2) 2 + (1 + 3) 2= 41, PA + Pb minimum length, then the minimum value is 41. (2) find the maximum value: as shown in the figure: connect AB and extend, intersect the x-axis at point P, take any point P ', connect AP', BP ', in △ ABP', according to the nature of the triangle, the difference between the two sides is less than the third side, that is AP '- BP' < AB, ｜ we can know that AB is the maximum value, a (- 2,3), B (3,1), ab = (3 + 2) 2 + (3-1) 2 = 29, If the length of pa-pb is the largest, the maximum is 29

Simple calculation 2.1 △ 11

2.1÷11
= 210 /11
two hundred and ten-elevenths
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If you devote yourself to study, you will become a great tool in the future,
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"Choose as satisfactory answer"

If the generatrix length of a cone is 5 cm and the bottom radius is 3 cm, the surface area of the cone is ()
A. 15πcm2B. 24πcm2C. 30πcm2D. 39πcm2

If the radius of the bottom is 3cm, the perimeter of the bottom is 6 π cm, the side area of the cone is 12 × 6 π × 5 = 15 π cm2, the bottom area is 9 π cm2, and the surface area of the cone is 15 π + 9 π = 24 π cm2

One in seven times 57 and one in six plus 41 and one in three times three in four plus 51 and one in four times four in five

The original formula = (70 + 7 / 6) X6 / 7 + (60 + 6 / 5) X5 / 6 + (50 + 5 / 4) X4 / 5 + (40 + 4 / 3) X3 / 4 + (30 + 3 / 2) x2 / 3 = 70x6 / 7 + 7 / 6x6 / 7 + 60x5 / 6 + 6 / 5x5 / 6 + 50x4 / 5 + 5 / 4x4 / 5 + 40x3 / 4 + 4 / 3x3 / 4 + 30x2 / 3 + 3 / 2x2 / 3 = 60 + 1 + 50 + 1 + 40 + 1 + 30 + 1 + 20 + 1 = 205 can you solve your problem