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Which of the six corner elements of a triangle can determine a triangle?
1) Three sides
2) Two corners and one side (any side)
3) Angle between two sides
4) A right triangle has a right side and a hypotenuse
Are three angles congruent to two equal triangles
Such as the question, I have drawn many triangles, three angles correspond to equal 2 triangles should be congruent ah, please answer the math master, not congruent
Unequal
Regular triangles of different sizes are all 60 degrees, but different sizes are unequal
Are there two triangles congruent whose angles and sides are equal?
If we don't say corresponding equality, is it congruent, for example?
I mean, if it's not an equilateral triangle, one of the triangles may be two corners holding one side together, and if a triangle is the corresponding side of two corners and one of the corners, because there is no "corresponding equal", it's not congruent. I don't know if this idea holds.
To be congruent, two triangles with equal angles and sides must be congruent!
Triangle ABC and triangle def, ∠ B = e, ab = De, ∠ C = e, then the triangle ABC is AAS, and the triangle DEF is ASA, so it is not congruent, look at the topic carefully!
Corresponding equality is different from separate equality!
Let n be a positive integer, and prove that n (n ^ 2-1) (n ^ 2-5n + 26) is divisible by 120
[note] there are two conclusions
【1】 The product of five continuous natural numbers must be divisible by 120
【2】 The product of three continuous natural numbers must be divisible by 6
[certification]
∵n²-5n+26
=(n²-5n+6)+20
=(n-3)(n-2)+20.
The original formula = (n-3) (n-2) (n-1) n (n + 1) + 20 (n-1) n (n + 1)
Combined with the above two conclusions, you can prove that you will
If P & nbsp; is a point on the ellipse, then | PF2 | = | F1F2 |, and the distance from F2 to Pf1 is equal to the length of the minor axis of the ellipse, then the eccentricity of ellipse C is______ ．
Point P is on the ellipse C, and | Pf1 | 124; Pf1 | + | PF2 | = 2A, and | PF2 | = | PF2 | = | PF2 | | PF2 | = 2A, and | PF2 | = | F1F2 | you can get D is the midpoint of Pf1, so DF1 = 12 | Pf1 | Pf1 ? 1 ? Pf1 ? is a-a-c-c-c, in RT \\124; df1; df1f1; df1f1; df1f1f1; DF
Put prime numbers in brackets
（）＋（）＋（）＋（）＋（）＋（）＋（）＝（）＋（）＋（）＋（）＋（）＋（）＝（）＋（）＋（）＋（）＋（）＝（）＋（）＋（）＋（）＝（）＋（）＋（）＋（）＋（）＝21
Prime numbers in parentheses
（3）＋（3）＋（3）＋（3）＋（3）＋（3）＋（3）＝（2）＋（2）＋（2）＋（2）＋（2）＋（11）＝（2）＋（2）＋（2）＋（2）＋（13）＝（2）＋（3）＋（3）＋（13）＝（2）＋（2）＋（3）＋（7）＋（7）＝21
Given that positive numbers a and B satisfy 2B + AB + a = 30, find the minimum value of y = 1 / ab
We learned basic inequalities
2b+a≥2√(2ab)
ab+2√(2ab)≤30
2√(2ab)≤30-ab
(ab)²-68ab+900≥0
Ab ≥ 50 (rounding off) or ab ≤ 18 (take the equal sign if and only if 2B = a)
So the minimum value of 1 / (AB) is 1 / 18, where a = 6 and B = 3
Given the function f (x) = b * a ^ x (where a, B are constant, tangent a > 0, a ≠), the image passes through points a (1,6), B (3,24)
If the function g (x) = root sign (1 + A ^ x-m * B ^ x) is meaningful when x ∈ (- ∞, 1], find the value range of real number M
Given the function f (x) = b * a ^ x (where a, B are constant, tangent a > 0, a ≠), the image passes through points a (1,6), B (3,24)
∴ 6=b*a,24=b*a^3
∴ a=2,b=3
That is, 1 + A ^ x-m * B ^ x ≥ 0 is always true when x ∈ (- ∞, 1]
The results show that ∧ m * B ^ x ≤ 1 + A ^ x is constant when x ∈ (- ∞, 1]
When x ∈ (- ∞, 1], m ≤ (1 / b) ^ x + (A / b) ^ x is constant
When x ∈ (- ∞, 1], m ≤ (1 / 3) ^ x + (2 / 3) ^ x is constant
Y = (1 / 3) ^ x + (2 / 3) ^ x is a decreasing function. When x = 1, the minimum value of 1 is obtained
∴ m≤1
2X + 3 of x = 5 of 36
Original formula: 2x + X / 3 = 36 / 5
General score: (30x + 5x) / 15 = 108 / 5
Simplification: 35x = 108
x=108/35
Is the original answer wrong?
Let the probability density of random variable (x, y) be f (x, y) = {K (6-x-y), 0
Casually looking for a probability and statistics textbook, there are the same examples above
The distribution function of this problem has five branches, which are: an expression in two three four quadrants, which should be 0; the other four branches are in the first quadrant, and the points (x, y) fall in the rectangle 0
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- 10. In the triangle ABC, ∠ C = 90 degrees, CD ⊥ AB, ∠ B = 56 degrees, then ∠ DCA
- 11. As shown in the figure, in △ ABC, ab = AC, point D is the midpoint of DC, and point E is on ad. find out congruent triangles in the figure and explain why they are congruent Yeah
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- 14. Two congruent triangles of similar and equal circumference
- 15. Proof: there are two equal triangles corresponding to the bisector of two angles and one of them
- 16. Two angles and the opposite sides of one of them correspond to the congruence of two equal triangles. Do the two angles refer to the two separate angles of two triangles This sentence is incomprehensible What is the equivalence of the opposite sides of a corner
- 17. There are two congruent triangles with two equal angles and one side. Why? Give a counterexample It is suggested to avoid the following multiple-choice questions when preparing the test paper Only the following elements of two triangles are equal, so it can't be determined that two triangles are congruent () (A) Two corners and one side; (b) two sides and included angle; (C) Three corners; (d) three sides We should strictly follow the format of "congruence of two triangles with two corners and the opposite side of one corner corresponding to the same". We should not omit "the opposite side of one corner". We should not use ambiguous language such as "congruence of two triangles with two corners and one side corresponding to the same" to determine congruence of two triangles in class In understanding this concept, do not confuse correspondence with the corresponding edge of congruent triangle. As long as two triangles have two equal angles and one equal side, we can regard these two triangles as having two equal angles and one equal side. It is emphasized in the textbook that there are two equal triangles corresponding to two corners and the opposite side of one corner. How to understand the correspondence here? First of all, I want to make it clear that correspondence and corresponding edge are not a concept. If we stand on the platform of congruence of triangles and understand the correspondence here based on the corresponding edge of congruence triangles, then this problem is very difficult to solve. I think the correspondence here has something in common with the correspondence in the concept of function. The first triangle has one side with a length of 3cm, and only the second triangle has one side with a length of 3cm. We should regard these two triangles as having a pair of equal sides, which means the correspondence here.
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