At least one way to describe the three words is dawn, solemnity, bowing, trembling, exhausted, leisurely and immortal At least one way to describe the three words is dawn, solemnity, bowing, trembling, exhausted, leisurely and immortal fast

At least one way to describe the three words is dawn, solemnity, bowing, trembling, exhausted, leisurely and immortal At least one way to describe the three words is dawn, solemnity, bowing, trembling, exhausted, leisurely and immortal fast

At dawn, before the night sky could open its drowsy eyes, an octogenarian, dragging his exhausted body, walked to a very secluded place. He was going to visit his son, who had left him yesterday. His son, in his forties, lost his precious life by saving a drowning child. At that moment, many people hesitated, and he jumped out of the water calmly, This is a real hero whose spirit will last forever

With dawn, rubble, cellar, bow, trembling, dirty suitcase sanctions, gone, solemn, absurd, forgetful

When another dawn came, he went out of the cellar and stepped on the rubble to look for his relatives. In just one night, the once solemn church had already disappeared. The suitcases and filth were piled up all over the place, completely devoid of the old style. He felt his head for a long time, as if he wanted to recall yesterday's prosperity. However, except for grandma's trembling figure at the time of the explosion, He can't remember anything

As shown in the figure, the quadrilateral ABCD is a parallelogram, and ⊙ o with ab as the diameter passes through point D, e is the point on ⊙ o, and ∠ AED = 45 ° if BC = 3 √ 2, AE = 4, calculate De

∵ ABCD is a parallelogram, ∵ ad = BC = 3 √ 2, connecting BD, AB is the diameter, ∵ ADB = 90 °, and ∵ abd = ∠ AED = 45 °, ∵ Δ abd is an isosceles right triangle, ∵ ad = BD = 3 √ 2, ab = √ 2 * ad = 6, OD ⊥ ab

6-3-4-10, 24 o'clock

（-3）*[(-4)+(-10）]+6=(-3)*(-6)+6=24;
(-10)*[6/(-3)]-(-4)=(-10)*(-2)+4=24;
(-3)*[[6+(-4)+(-10)]=(-3)*(-8)=24;

The two cars leave from a and B at the same time, and they meet at 48km away from the destination when they are 4 hours old. It is known that the speed of the local train is 3 / 5 of that of the express train, and there is much distance between a and B
Less kilometers?

It is known that the speed of slow train is 3 / 5 of that of fast train, that is, the speed ratio of slow train to fast train is 3:5,
We can get: when we meet, the slow car runs 3 / (3 + 5) = 3 / 8 of the whole journey,
It is known that two cars meet at a distance of 48 km from the midpoint
It can be concluded that the distance between a and B is 48 △ (1 / 2-3 / 8) = 384 km

Isosceles triangle known two waist 5cm, find the bottom

Only know two sides can not find the bottom edge, also need to know the vertex size, so you can use the cosine theorem

It is known that a, B, C are all positive numbers, and they are not equal to 1. If the real numbers x, y, Z satisfy AX = by = CZ, 1x + 1y + 1z = 0, then the value of ABC is equal to ()
A. 1B. 2C. 3D. 4

Let AX = by = CZ = K (k > 0), then x = logak, y = logbk, z = logck, ｜ 1x + 1y + 1z = logka + logkb + logkc = logkabc = 0, ｜ ABC = 1

Solutions to the problem of tree planting in the fourth grade mathematics volume II of PEP

Planting on both ends: number of trees = number of segments + 1
Plant at one end and not at the other: number of trees = number of segments
No planting at both ends: number of trees = number of segments - 1
Ring: number of trees = number of segments

For a cylinder with a bottom radius of 2cm, the area of the side expanded view is the square of 12 π cm, and the height of the cylinder is (), which is now used,

12π/(2*2*π)=3

Let the sum of the first n terms of an be Sn, if A1 = 1, S6 = 4S3, then A4 and Sn are obtained

Obviously, the common ratio Q ≠ 1
S6=1x(1-q^6)/(1-q)=4*[(1-q^3)/(1-q)]
(1-q³)(1+q³)=4(1-q³）
1+q³=4
q³=3 q=³√3
So A4 = a1xq & # 179; = 1x3 = 3
sn=1x(1-qⁿ)/(1-q)= [(³√3)ⁿ-1]/(³√3-1)