Unit summary of solving the first degree equation of one variable in the fifth unit of Elementary Mathematics More than 500 words

Definition of unary linear equation: an integral equation with only one unknown number and the highest degree of the unknown number is 1 is called unary linear equation. General form: ax + B = 0 (a, B are constants, a ≠ 0). Unary linear equation has only one solution. The solution is to move the unknown number to one side by moving the term, and then the constant to one side

Volume 1 unit 28 ~ 32 summary

Is it "the plane figure in life" (this is in my book)
The conclusion is simple
It's a sentence
It mainly talks about the definition of plane figure, arc and sector
In fact, this section is about making you learn to find graphics in your life
Feeling graphics is inseparable from our life

Given the X-1 power of the function f (x) = - 1 + loga (x + 2) (a > 0 and a ≠ 1), G (x) = (1 / 2), if the image of the function f (x) = f (x) - G (x) passes through the point (2,1 / 2), it is proved that the equation f (x) = 0 has a unique solution on (1,2). Given the quadratic function y = f (x), when 3 ≤ x ≤ 6, f (x) ≤ f (5) = 3, F (6) = 2 (1) find the expression of F (x); (2) if the function g (x) = f (x) + (M-10) x-m + 1 has the maximum value of - 87 / 4 in the interval [- 1,2], find the value of M; (3) if f (x) ≤ (3-2a) t + 1 belongs to [3,6] for all x and a belongs to [- 1,1], find the value range of real number t

It is proved that f (x) = f (x) - G (x) = X-1 power of loga (x + 2) - 1 - (1 / 2)
When x = 2, f (x) = 1 / 2, loga4-1-1 / 2 = 1 / 2, the solution is a = 2
F (x) = X-1 power of log2 (x + 2) - 1 - (1 / 2)
F (1) = log2 (3) - 2 is less than 0
F (2) = log2 (4) - 1-1 / 2 = 1 / 2 > 0
The equation f (x) = 0 has a unique solution on (1,2)

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Simplification [(2m-n) / (M + n) - n ^ (m-n)] / [{m-2n} ^ (M + n)]

[(2m-n)÷(m+n)-n÷(m-n)]÷[{m-2n}÷(m+n)]
=【（2m-n）(m-n)-n（m+n）】/(m-n)(m+n)x (m+n)/(m-2n)
=(2m²-3mn+n²-mn-n²)/（m-n）(m-2n)
=2m(m-2n)/（m-n）(m-2n)
=2m/（m-n）
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Finding the chord length of the line x + 2y-3 = 0 cut by the circle C: (x + 2) square + y square = 16

Make a vertical line through the center of the circle. Then connect the center of the circle and a focal point
The formula of the distance from the origin to the straight line can find a right angle side
The radius is hypotenuse
Finding half of the chord length with the stock purchase theorem
Multiply by 2 to find the chord length

How to write English words in December

January,February,March,April,May,June,July,August,September,October,November,December.

It is known that the four numbers in turn form an arithmetic sequence, the sum of squares of the four numbers is 94, and the product of the first and the last two numbers is 18 less than the product of the middle two numbers

Let these four numbers be n-3k, n-k, N + K, N + 3K (k > 0)
There are
(n-3k)^2+(n-k)^2+(n+k)^2+(n+3k)^2=94
And (n-3k) (n + 3K) - (n-k) (n + k) = - 18
The solution is k = 3 / 2, n = plus or minus 7 / 2
So it can be - 1,2,5,8
Or 1, - 2, - 5, - 8

Find the range of the following functions: (1) y = x2-2x + 4 (2) y = - 2x2 + 8x-1, X ∈ [0,3] (3) y = x + √ (1-2x)

1) Y = (x-1) ^ 2 + 3, so the range is [3, + ∞)
2) Y = - 2 (X-2) ^ 2 + 7, because 0

Unit summary of solving the first degree equation of one variable in the fifth unit of Elementary Mathematics More than 500 words