Grade 6 Volume 2 mathematics talent course unit quality evaluation {2} the answer is urgent!

Grade 6 Volume 2 mathematics talent course unit quality evaluation {2} the answer is urgent!

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Problems on page 114 of the sixth grade volume 2 of the course for talents published by people's Education Press
The second question of improving ability on page 114 of PEP elite course for Grade 6 Volume 2
The time ratio of a, B and C is 6:7:8. Now it takes three people the same time to complete the task of building a 3650 meter road. How many meters should they build?
Today, my brain is short circuited and I'm a little slow to respond. I hope people with lofty ideals can send me an answer as soon as possible until 9:30

3650/【6+7+8】
=3650/20
=182.5
182.5*6
182.5*7
182.5*8

A and B leave from two places at the same time. Car a travels 54 kilometers per hour and car B 48 kilometers per hour. When they meet, car a travels 30 kilometers more than car B. how many hours did the two cars meet?

54-48 equals 6
30 / 6 equals 5
So it's five hours

After a decimal point is removed, the number obtained is 7.2 more than the original number. What is the original number?
It's a question for the fourth grade of primary school

0.8
Let the original number be X
10x=x+7.2

The distance between a and B is 270 kilometers. A and B leave from a and B at the same time. Car a travels 42 kilometers per hour, while car B travels 48 kilometers per hour. How many hours later do the two cars meet?

270 (42 + 48) = 270 (90) = 3 (hours); a: the two cars meet in 3 hours

Given two circles C1: (x-1) 2 + (Y-1) 2 = 2 C2: (x + 5) 2 + (y + 6) 2 = 4, judge the position relationship of two circles and find the equation of common tangent
Given two circles C1: (x-1) 2 + (Y-1) 2 = 2 C2: (x + 5) 2 + (y + 6) 2 = 4, judge the position relationship of two circles and find the equation of common tangent
There are four common tangent lines instead of common chord

To judge the position relationship of two circles is to compare the center distance of circle C1 with the sum of two radii. The center distance of circle C1 is (1,1) R1 = root sign 2, the center distance of circle C2 is (- 5, - 6) R2 = 2, the center distance of circle is (1 + 5) ^ 2 + (1 + 6) ^ 2 = root sign 85r1 + R2 = 2 + follow sign 2

A car from a to B, 60 km per hour, has walked 120 km, equivalent to three fifths of the whole journey. How many hours to complete

Whole journey: 120 △ 3 / 5 = 200 km
For complete process: 200 △ 60 = 10 / 3

Given that XY is reciprocal to each other and Mn is opposite to each other, try to find the new quadratic power of polynomial xym + N + and the quadratic power of Y
The new is X

XY is reciprocal to each other -- "xy = 1,
Mn is opposite to each other -- "m + n = 0,
——》xym+n+x^2y^2=m+n+(xy)^2=0+1^2=1.

It is known that the speed of the local train is 56 times that of the express train. The two trains are going towards each other at the same time from station a and B, and they meet at the place 4 kilometers away from the midpoint. How many kilometers is the distance between station a and B?

(4 × 2) / (65 + 6 − 55 + 6) = 8 / 111, = 88 km. A: the distance between the two stations is 88 km

Observe the following operations and fill in the blanks: 1 × 2 × 3 × 4 + 1 = 25 = 52; 2 × 3 × 4 × 5 + 1 = 121 = 112: 3 × 4 × 5 × 6 + 1 = 361 = 192 According to the above results, conjecture and study: (n + 1) (n + 2) (n + 3) (n + 4) + 1=______ ．

From 1 × 2 × 3 × 4 + 1 = 25 = 52 = (02 + 5 × 0 + 5) 2; 2 × 3 × 4 × 5 + 1 = 121 = 112 = (12 + 5 × 1 + 5) 2; 3 × 4 × 5 × 6 + 1 = 361 = 192 = (22 + 5 × 2 + 5) 2 It is found that: (n + 1) (n + 2) (n + 3) (n + 4) + 1 = (N2 + 5N + 5) 2. It is proved that the left side of the equation = (n + 1) (n + 2) (n + 3) (n + 4) + 1 = (N2 + 3N + 2) (N2 + 7n + 12) + 1 = N4 + 7n3 + 12n2 + 3n3 + 21n2 + 36N + 2n2 + 14N + 25 = N4 + 10n3 + 35n2 + 50N + 25 = N4 + 2n2 (5N + 5) + (5N + 5) 2 = (N2 + 5N + 5) 2 = the right side of the equation