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（）.0（）÷（）=0.（）（）…… three （）8.（）（）÷1.（）=（）2.（） It's vertical~
Sorry, I don't understand! Where are you? I'm in grade five, too. I don't seem to have this problem!
The cavalry of the Eighth Route Army pursued the Japanese invaders at a speed of 22km per hour. When they arrived at a village, they learned that the Japanese invaders had fled two hours ago. It is known that the speed of the Japanese invaders' escape is 22km per hour. How many hours can the cavalry of the eighth Route Army catch up with the enemy?
Wrong number. The speed at which the Japanese escaped was 12 km per hour
The speed of the Eighth Route Army is the same as that of the Japanese aggressors, so it is impossible to catch up with them
This is a pursuit problem. If you don't understand it, you can combine it with the actual situation and think about it carefully, and you will understand it!
If the speed is different, it is easy to calculate: the distance difference between the two △ the speed difference between the two = catching up time
（12×2）÷（22-12）
=24÷10
=2.4 (hours)
Winter vacation homework and life math answers grade five
Picture
(1) The race is 8000 meters, and the time of Baisha is 26 minutes and 40 seconds. What's their average speed per second?
(2) There are seven teams in this game. The wind and rain team ranks second from the bottom. How many are they?
(3) There is a building with four solar collectors installed on the top of the building. The bottom of each triangle is 5 meters and the height is 2.7 meters?
The second floor of the basic question is wrong!
1. Time 26 minutes 40 seconds = 1600 seconds
Average speed = 8000 / 1600 = 5m / S
2. Sixth place
3. Area of each triangle = 1 / 2 * 5 * 2.7 = 6.75 square meters
Total area of 4 triangles = 4 * 6.75 = 27 square meters
Given that a and B are opposite to each other, C and D are reciprocal to each other, x = 3 (A-1) - (a-2b), y = the square of C multiplied by the square of D + D - (C / D + C-1). Find (3 / 2x + y) - (6 / 3x-2y)
x=3a-1-a+2b=2(a+b)-1=-1
There seems to be something wrong with y
Given 3sin β = sin (2 α + β), (1) prove Tan (α + β) = 2tan α, (2) find the maximum of Tan β
The first question meeting, mainly the second one
I haven't learned derivative yet. What should I do?
3sinβ=sin(2α+β)=sin2αcosβ+cos2αsinβ
Divide both sides by cos β
tanβ=sin2α/(3-cos2α)
Let 2 α = X
y=tanβ=sinx/(3-cosx)
Derivation
Y '= (3cosx-1) / (3-cosx) ^ 2, the range of X is limited in one cycle
Obviously, when cos = 1 / 3, SiNx = 2skrt2 / 3, Tan β is the largest
The maximum is sqrt2 / 4
Solving equation 2x ^ 2-4x + 3 √ x ^ 2-2x + 4 = 6
2x^2-4x+3√x^2-2x+4=6
2(x²-2x+4)-8+3√(x²-2x+4)=6
Let √ (X & # 178; - 2x + 4) = y
Then 2Y & # 178; - 8 + 3Y = 6
That is, 2Y & # 178; + 3y-14 = 0
（2y+7)(y-2)=0
The solution is y = 2 or ty = - 7 / 2
So √ (X & # 178; - 2x + 4) = 2
That is X & # 178; - 2x + 4 = 4
x（x-2)=0
The solution is x = 0 or x = 2
If you don't understand, please continue to ask
If you ask questions from your mobile phone, just click "satisfied" in the upper right corner of the client
Given that a is similar to diag (1 2 3 4), then the eigenvalue of a * is?
A is similar to diag (1, 2, 3, 4), so the eigenvalues of a are 1, 2, 3, 4
|A|=1*2*3*4=24
AA*=|A|E
A*=|A|A^(-1)=24A^(-1)
So the eigenvalue of a * is 24 * 1 ^ (- 1) 24 * 2 ^ (- 1) 24 * 3 ^ (- 1) 24 * 4 (- 1)
That is 24 12 8 6
(2x + 1) square + 2 (2x + 1) + 1 = the square of 0 3x + 5 (2x + 1) = 0
(2x + 1) square + 2 (2x + 1) + 1 = 0
(2x+1+1)²=0
2x+2=0;
x=-1;
The square of 3x + 5 (2x + 1) = 0
3x²+10x+5=0;
Δ=100-3×4×5=40;
x=(-10±√40)/6=(-5±√10)/3;
If you don't understand this question, you can ask,
Let u be r, a = {x | x ^ 2 + PX + 12 = 0}, B = {x | x ^ 2-5x + q = 0}, if (Cu A) ∩ B = {2}, a ∩ (Cu b) = {4}, find a ∪ B
Cub is a complement
(Cu A) ∩ B = {2} --- > 2 ∈ B substitute x = 2 into x ^ 2-5x + q = 0 to get: 4-10 + q = 0, q = 6 solve the equation x ^ 2-5x + 6 = 0 to get: X1 = 2, X2 = 3, so B = {2,3} a ∩ (Cu b) = {4} --- > 4 ∈ a substitute x = 4 into x ^ 2 + PX + 12 = 0 to get: 16 + 4P + 12 = 0, P = - 7 solve the equation x ^ 2-7x + 12 = 0 to get: X1 = 3, x2 = 4, so a = {3,4
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