Second grade physics Volume 1 page 85 question 3 Figure 4.2-6 shows the image of temperature change with time when a substance melts. According to what characteristics of the image, it can be judged that the substance is a kind of crystal? What is its melting point? How long does it last from the beginning of crystal melting to the complete melting of all crystals?

Second grade physics Volume 1 page 85 question 3 Figure 4.2-6 shows the image of temperature change with time when a substance melts. According to what characteristics of the image, it can be judged that the substance is a kind of crystal? What is its melting point? How long does it last from the beginning of crystal melting to the complete melting of all crystals?

Its temperature remains constant for a certain period of time. This temperature is its melting point (about 80 ℃). It lasts about 15 minutes

English unit 9 8 10 words and key phrases in the eighth grade of PEP
The more the better, the faster the better

This is very troublesome（ pl.mice )snakechildpigrabbitcompanycostasleepchoosepresentopengivenratherinsteadenternearlysangclearlywinnerinterestedencourageprogresssuggestbesidesmen...

People's education press English grade 8 Volume 2 unit 8 2D text, please type out the original and translation

P58   Unit8     2 dAmy:Steve Did you decide which book to choose for English class? Steve: Yes, little women. I've finished reading it. Amy: Wow, you're so fast. What's in this book? Steve: it's a good book, so it's over in a minute. Which book did you choose? Amy: I chose treasure island, But I haven't finished. I've only read 25 pages. Steve: did you at least read the brief introduction on the back of the book? Amy: Yes, I have. It looks interesting. Steve: you should read it quickly. After reading, you should hand it in within two weeks. Amy: Yes, I know. I'll finish it quickly. Note: Chinese call it after reading, Americans call it book report; ----------------------------------------------------------------------------------------------------
Note: please see the attachment:
Original text of lesson 2D in unit 8, Volume 2, Grade 8, people's education press, spring 2014

Given the circles C1: (x + 1) &# 178; + Y & # 178; = 1 and C2: (x-1) &# 178; + (Y-3) &# 178; = 10, the line passing through the origin o intersects C1 at P and C2 at Q, the trajectory equation of the midpoint m of PQ line segment is obtained

Let the linear equation be y = KX, the coordinates of P point be (x1, Y1), and the coordinates of Q point be (X2, Y2)
We can get P (- 2 / (k ^ 2 + 1), - 2K / (k ^ 2 + 1)), q ((2 + 6K) / (k ^ 2 + 1), (6K ^ 2 + 2K) / (k ^ 2 + 1))
So the abscissa of M is X3 = 3K / (k ^ 2 + 1), and the trajectory equation is obtained by substituting k = Y / X
x^2+(y-3/2)^2=9/4

As shown in the figure, in △ ABC, ab = AC, point O is within △ ABC, and ∠ OBC = ∠ OCA, ∠ BOC = 110 °, calculate the degree of ∠ a

∫ AB = AC, ∫ ABC = ACB, and ∫ OBC = OCA, ∫ ABC + ACB = 2 (∫ OBC + OCB), ∫ BOC = 110 °, ∫ OBC + OCB = 70 °, ∫ ABC + ACB = 140 °, ∫ a = 180 ° - (∫ ABC + ACB) = 40 °

① When x > - 2, simplify | X-6 | + | x + 2 | 2. When x is all real numbers, simplify: | x + 5 | - | X-2|

1. When x = 6, X-6 + X + 2 = 2X-4
2.x

If vector a = (2,3, - 4) B = (- 4, - 3, - 2) B = half x-2a, then vector x is equal to

letx= ( x1.y1,z1)b= (1/2)x -2a(-4,-3,-2) = ( (1/2)x1 -4, (1/2)y1-6, (1/2)z1+8)=>(1/2)x1 -4 =-4x1= 0and(1/2)y1-6 =-3y1=6and(1/2)z1+8 =-2z1=-20x =(0,6,-20)

Additional questions: as shown in the figure, it is known that △ ABC is inscribed in ⊙ o, AB is the diameter, ∠ CAE = ∠ B. verification: AE and ⊙ o are tangent to point a

It is proved that ∵ AB is the diameter, ∵ ACB = 90 degree, ∵ BAC + ∵ B = 90 degree, and ∵ CAE = ∵ B, ∵ BAC + ∵ CAE = 90 degree, that is, ∵ BAE = 90 degree, so AE and ⊙ o are tangent to point a

If the equation (2 (KX + 3)) / 3 + 0.5 = (5 (2x + 3)) / 6 has innumerable solutions, k =?

It is reduced to 4kx-10x = 0. If there are innumerable solutions, then x is always 0 at any value, so k = 2.5

It is known that the eccentricity of ellipse C; X & # 178 / / A & # 178; + Y & # 178 / / B & # 178; = 1 (a ﹥ B ﹥ 0) is 1 / 2, the line L passes through point a (4,0) B (0,2) and is tangent to ellipse C and point P
(1) Solving the equation of ellipse C
(2) Is there a straight line m passing through point a (4,0) intersecting with ellipse C at two different points m, N, such that 36iapi & # 178; = 35iami * iani? If so, try to find the equation of straight line m; if not, explain the reason
PS: I have solved the first question of this problem, and the equation of ellipse is x ^ 2 / 4 + y ^ 2 / 3 = 1 (a > b > 0), and the coordinate of P point is (1,3 / 2). Please help me to look at the second question, thank you~

The linear equation y = K (x-4) is set as the linear equation y = K (x-4) 3x & \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\+ 4K & # 178;) ∵ 36iapi