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If the image with positive scale function y = 2mx passes through a (x1, Y1) and B (X2, Y2), then
2m > 1, M > 0, M > 1 / 2
Given the two points a (x1, Y2), B (X2, Y2) on the image with inverse scale function y = 1-2m / x, when X1 < 0 < X2, there is a value range of Y1 > Y2 for M
It is Y1 > Y2
∵ when x1 ＜ 0 ＜ X2, there is Y1 ＞ Y2
∴1-2m1/2
RELATED INFORMATIONS
- 1. The known points a (x1y1), B (x2y2) C (x3y3) are all on the image with inverse scale function y = - 4 / X And x1 ＜ 0 ＜ x2 ＜ X3 1. Draw the image of this function and mark the position of ABC. 2. According to the image, compare the sizes of Y1, Y2 and Y3
- 2. It is known that a (x1, Y1), B (X2, Y2) are all on the image of y = 6 / X. if x1x2 = - 3, then the value of y1y2 is————
- 3. It is known that a (x1, Y2) and B (X2, Y2) are on the function image of y = 6 / X if x1x2 = - 3, y2y2y2=_____
- 4. There are two points (x1, Y1) and (X2, Y2) on the image with inverse scale function y = K + 1 of X, if x1
- 5. ① Given that points a (x1, Y1) and B (X2, Y2) are on the image with inverse scale function y = 4 / x, if X1 > X2, try to compare the sizes of Y1 and Y2 ② The inverse scale function y = K / X (K ≠ 0) is known. When x ＞ 0, y increases with the increase of X. the quadrant of the image of the first-order function y = kx-k is calculated
- 6. It is known that the shape and size of the image of the quadratic function y = a (x + m) &# 178; + k are the same as the parabola y = - 1 / 2 (x-4) &# 178, And the vertex of the image is just the intersection of the line y = 3 / 2X-4 and y = - 2x, so we can find the analytic expression of the quadratic function
- 7. If there are three points (- 4, Y1), (- 5, Y2), (- 6, Y3) on the parabola y = x2-4x + m, then the size relation of Y1, Y2, Y3 is () A. Y1 ＞ Y2 ＞ y3b. Y1 ＜ Y2 ＜ y3c. Y1 ＞ Y3 ＞ Y2D
- 8. It is known that the images of the linear functions Y1 = 2x + A and y2 = - x + B pass through the points a [- 2,0], and intersect with the Y axis at two points B.C It is known that the images of the first-order functions Y1 = 2x + A and y2 = - x + B pass through the points a [- 2,0], and intersect with the Y axis at two points B.C. (1) find the values of a and B; (2) draw the images of the two first-order functions in the same plane rectangular coordinate system; (3) find the area of △ ABC
- 9. Given the function y = (M & # 178; - M) x & # 178; + MX + (M + 1) (M is a constant), when m is a value, 1. The function is a linear function 2. The function is a quadratic function
- 10. The image of the quadratic function Y1 = AX2 + BX + C and y2 = KX + B intersects in the x value range of a (- 2,4) B (8,2) which makes Y1 > Y2 hold Before 22:20 Before 22:30
- 11. As shown in the figure, the straight line y = KX + B passing through the point F (0,1) intersects the parabola y = 1 / 4x ^ 2 at two points m (x1, Y1) and n (X2, Y2) (where X1 < 0, x2)
- 12. Given that point a (x, y) moves on the parabola y = 4x, find the minimum value of Z = x + Y / 2 + 3 It's the 9th question of 42 sides of 1-1 elective course of famous teacher No.1!
- 13. As shown in the figure, the straight line y = - 2 / 3x + 12 intersects the x-axis and y-axis at two points B and a respectively, and the vertical bisector of line AB intersects the x-axis and y-axis at two points c and D (1) respectively A. (2) calculate the area of △ ACD
- 14. As shown in the figure, the straight line y = -43x + 8 intersects the x-axis and y-axis at two points a and B respectively, and the vertical bisector of line AB intersects the x-axis and y-axis at two points c and D respectively. (1) calculate the coordinates of point C; (2) calculate the area of △ BCD
- 15. A straight line with an inclination angle of quarter passes through the focus of the parabola y = 8x, and intersects with the parabola at two points a and B. the length of line AB is calculated
- 16. Through the focus F of the parabola, make a straight line not perpendicular to the axis of symmetry, the parabola intersects a and B, and the vertical bisector of line AB intersects the axis of symmetry n
- 17. If the distance from the vertex of the parabola y = x-6x + C-2 to the X axis is 3, then the value of C is a () plus process
- 18. Parabola y = x & sup2; - 2x-3 intersects with X axis and points a and B, intersects with y axis and points C. 1 find the vertex coordinates of parabola. 2 let the intersection of line y = - x + 3 and Y axis be D, and at any point E (not coincident with B and D) on line D, the intersection line BC and point F passing through three points a, B and E, try to judge the shape of △ AEF and explain the reason,
- 19. As shown in the figure, we know that the parabola y = x2 + BX + C passes through two points a (1,0), B (0,2), and the vertex is d (1) Find the analytical formula of parabola; (2) rotate △ OAB clockwise about point a for 90 ° and point B falls to point C, then translate the parabola along Y-axis and pass through point C to find the functional formula of the image after translation; (3) let (2) after translation, the intersection of parabola and y-axis be B1 and the vertex be D1, if point n is on the parabola after translation and the area of △ nbb1 is △ nd Double the area of D 1, find the coordinates of point n
- 20. As shown in the figure, the vertex of the parabola y = x2 + BX + C is d (- 1, - 4), intersects with the Y axis at points c (0, - 3), and intersects with the X axis at two points a and B (point a is on the left side of point B) (1) (2) connecting AC, CD and ad, try to prove that △ ACD is a right triangle; (3) if point E is on the symmetry axis of the parabola, is there a point F on the parabola, so that the quadrilateral with a, B, e and F as the vertex is a parallelogram? If it exists, find out the coordinates of all the points f that meet the condition; if not, explain the reason