Given that the center of the circle is on the straight line 3x + 4y-5 = 0 and tangent to both coordinate axes, the equation of the circle is obtained,

Given that the center of the circle is on the straight line 3x + 4y-5 = 0 and tangent to both coordinate axes, the equation of the circle is obtained,


Let the center of the circle be (a, (5-3a) / 4) and tangent to the coordinate axis
The radius is equal to the absolute value of the coordinates
That is: r = | a | = | 5-3a | / 4
a=(5-3a)/4--> a=5/7
-a=(5-3a)/4-->a=-5
So there are two circles, and the equation is:
(x-5/7)^2+(y-5/7)^2=25/49
(x+5)^2+(y-5)^2=25



The equation for finding a circle whose center is on the straight line 3x-4y = 7 and tangent to both coordinate axes
It's better to write by hand


Let the center of the circle be (a, b), the radius be r, and the circle is tangent to the two coordinate axes. It shows that: a = ± B (1) a = B, so 3a-4a = 7 is solved, a = b = - 7. Then, the standard equation of r = 7 circle is: (X-7) square + (Y-7) square = 49 (2) a = - B, so 3A + 4A = 7 is solved, a = 1, B = - 1. Then, the standard equation of R = 1 circle is



Circle tangent to both axes and line 3x + 4y-4 = 0
1, the equation of the circle in the first quadrant which is tangent to the two coordinate axes and the line 3x + 4y-4 = 0____________
If the secant of circle x ^ 2 + y ^ 2-8x-2y + 12 = 0 is made through point P (3,0), then the linear equations of the longest and shortest chord are_____________
3. Given that P is a point on the circle (X-2) ^ 2 + (Y-5) ^ 2 = 1 and Q (2,3), then the maximum inclination angle of the line PQ___________ , minimum_________
4. Find a point P on the straight line X-Y + 2 √ 2 = 0, so that the tangent length from P to the circle x ^ 2 + y ^ 2 = 1 is the shortest, then the coordinate of point P is_________


1, the equation of the circle in the first quadrant which is tangent to the two coordinate axes and the line 3x + 4y-4 = 0____________ The distance between 3x + 4y-4 = 0 and the intersection a (4 / 3,0) of x-axis, and the intersection B (0,1) of y-axis is ab = ((16 / 9) + 1) ^ (1 / 2) = 5 / 3. Suppose the radius of circle R, then the area of triangle ABO = (1 / 2) * (4 / 3) * 1 = (1 / 2)