The positional relationship of circle C1: x2 + y2 = 4 and C2: x2 + y2-6x + 8y-24 = 0 is______ ．

The positional relationship of circle C1: x2 + y2 = 4 and C2: x2 + y2-6x + 8y-24 = 0 is______ ．

∵ circle C1: x2 + y2 = 4, center C1 (0, 0), radius 2, C2: x2 + y2-6x + 8y-24 = 0, that is, (x-3) 2 + (y + 4) 2 = 49, center C2 (3, 4), radius 7, the distance between the centers of two circles is equal to 9 + 16 = 5, just equal to the difference between the radii of two circles, so the two circles are inscribed, so the answer is: inscribed

How to calculate the position relation between two circles C1: x + y = 2 and C2: x + y-2x-1 = 0

The positional relationship between two circles C1: X & # 178; + Y & # 178; = 2 and C2: X & # 178; + Y & # 178; - 2x-1 = 0
C1：x²+y²=2
C2：(x-1)²+y²=2
The radius of the two circles is √ 2, and the distance between the center of the circle is 1, so the two circles intersect

How to judge the position relationship between two circles C1: x ^ 2 + y ^ 2 = 2 and C2: x ^ 2 + y ^ 2-2x-1 = 0

C1 radius, root 2, Center (0,0)
C2 radius, root 2, Center (1,0)
Center distance of circle is less than radius and greater than radius difference
So intersect