If the median of the two numbers is 5 and the median of the two numbers is 4, then the two numbers are

If the median of the two numbers is 5 and the median of the two numbers is 4, then the two numbers are

2 and 8

If we know that a and B are positive real numbers, a is the median of the equal difference of a and B, and B is the median of the equal ratio of a and B, then the relationship between AB and ab is / gods help

Because AB = B squared, AB / (AB) = B / A

It is known that a, B, a + B are equal difference sequence, a, B, AB are equal ratio sequence, and 0

a. B, a + B is an arithmetic sequence, B-A = a + B-B, so B = 2A
a. B, AB is an equal ratio sequence, B / a = AB / B, so B = A & sup2; a = 2, B = 4
0

It is known that AB is a positive real number, a is the mean of equivalency of AB, 1 / h is the mean of equivalency of 1 / A and 1 / B, and G (G > 0) is the mean of equivalency of AB, then the relation of AHG is B
A A≤H≤G
B H≤G≤A
C G≤A≤H
D G≤H≤A

Select b, 2A = a + B, 2 / h = (a + b) / AB, G ^ 2 = ab
From (a + b) ^ 2 > = 4AB to 4A ^ 2 > = 4G ^ 2 to a > = g
From 2 / h = 2A / G ^ 2 > = 2 / g to h

a. If B, C and D are positive real numbers, C is the sum of the equal mean of AB, and D is the equal mean of AB, the following results can be obtained:
ab＞cd ab≧cd
Which of the four formulas AB < CD ab ≤ CD is right?

ab≦cd
∵ D is the middle term of the equal ratio of ab ∵ AB = D & # 178;
∵ C is the mean of equivariance of ab ∵ a + B = 2C ≥ 2 √ AB = 2D
If C ≥ D, CD ≥ D & # 178; = ab
That is ab ≤ CD
As for the equal sign condition a = B, let a = b = C = D = 1, and the equal sign satisfy
So ab ≤ CD

Given that a, B, a + B are equal difference sequence, a, B, AB are equal ratio sequence, and 0 < logm (AB) < 1, what is the value range of M

The logarithm is significant, AB > 0, a, B, AB form an equal ratio sequence, let the common ratio be q (Q ≠ 0) a = AB / Q & # 178; > 0, so b > 0
a>0 b>0
a. If B, a + B is an arithmetic sequence, then 2B = a + A + B
b=2a
a. If B and ab form an equal ratio sequence, then
b²=a(ab)=a²b b=a²
2A = A & # 178; a (A-2) = 0, a = 0 (rounding off) or a = 2
b=2a=4 ab=8
0

It is known that a, B, a + B are equal difference sequence, a, B, AB are equal ratio sequence, and 0

a+a+b=2*b
So 2A = B
a*ab=b^2
So a = 0 or a = 2
And a, B, AB cannot be zero
So a = 2, B = 4
So AB = 8
So m

Given that a, B, a + B are equal difference sequence, a, B, AB are equal ratio sequence, and 0 < logm (AB) < 1, then the value range of M is______ ．

∵ a, B, a + B are equal difference sequence, ∵ 2B = 2A + B, that is, B = 2A. ∵ a, B, AB are equal ratio sequence, ∵ B2 = A2B, that is, B = A2. In conclusion, a = 2, B = 4, ab = 8. From 0 < logm (AB) < 1, we can get 0 < logm (8) < 1, ∵ m > 8. So the answer is (8, + ∞)

Given that a, B, a + B are equal difference sequence, a, B, AB are equal ratio sequence, and 0 < log (AB) < 1, then the value range of M?

If the logarithm is significant, AB > 0, a, B, AB form an equal ratio sequence, let the common ratio be q (Q ≠ 0) a = AB / Q > 0, so b > 0, a > 0, b > 0, a, B, a + B form an equal difference sequence, then 2B = a + A + B, B = 2A, a, B, AB form an equal ratio sequence, then B = a (AB) = AB, B = a, 2A = a, a (A-2) = 0, a = 0 (rounding off) or a = 2, B = 2A = 4, ab = 80

If a, B, a + B, are equal difference sequence, a, B, AB are equal ratio sequence, and 0

a. B, a + B, in arithmetic sequence, 2b = a + (a + b), B = 2A
a. B, AB is an equal ratio sequence, B ^ 2 = a * AB, B = a ^ 2
A = 2, or a = 0 (rounding)
b＝4
0＜logn（8）＜1＝logn（n）
n＞8