Find the value of √ (1996 * 1997 * 1998 * 1999 + 1)

Find the value of √ (1996 * 1997 * 1998 * 1999 + 1)


Let a = 1996
Then 1996 * 1997 * 1998 * 1999 + 1
=a(a+1)(a+2)(a+3)+1
=[a(a+3)][(a+1)(a+2)+1
=(a²+3a)[(a²+3a)+2]+1
=(a²+3a)²+2(a²+3a)+1
=(a²+3a+1)²
So the original formula = A & sup2; + 3A + 1 = 1996 & sup2; + 3 × 1996 + 1 = 3990005



Calculation: (square of 2000 + 1998) / (square of 1998-2000) * (square of 1997-1997) / (1998 * 2001-4)


Your shilling a = 1998,
The formula becomes:
[(a + 2) square + a] [a square - (a + 2) [(A-1) square - (A-1)] [a * (a + 3) - 4]
=Expand the formulas in square brackets
=(a square + 5A + 4) (a square - A-2) (a square - 3A + 2) (a square + 3a-4)
=(a+1)(a+4)(a+1)(a-2)(a-1)(a-2)(a-1)(a+4)
=(a + 1) square * (a + 4) square * (A-1) square * (A-2) square
It's much easier to calculate



What is the power 0 of 8? What is the power 0 of 1


If it's not a Brain Twister, it's one



3 to the 1099 power - 5 + | - 3 to the 1098 power + 1999 * (- 1) to the 1999 power?


Original formula = 3 × 3 ^ 1998-5 + 3 ^ 1998 + 1999 × (- 1) ^ 199
=4×3^1998-5-1999
=4×3^1998-2004



What is the single digit of 3 to the 251th power? Why?
The first power of 3 is 3, the second power of 3 is 9, the third power of 3 is 27, the fourth power of 3 is 81, the fifth power of 3 is 243, and the sixth power of 3 is 729
May I ask, (1) from the table, what are the rules of the single digits of the power of 3?
(2) What is the single digit of 3 to the 251th power? Why?
The number of the question will be on the table.


Consider only one bit, multiply by 3, and find that it must be a cycle of 4
3 9 7 1 3 9 7 1……
So 251 / 4 = 62 three
That is, the number of bits is the same as 3 ^ 3, which is 7



Find the sum of all the numbers in 1, 2, 3.1997, 1998 and 1999
I know the answer: (1 + 1999) + (2 + 1998). =2000×(2000÷2)=2000000


There are 200 times from 1 to 9; 45 * 200
There are 190 times from 1 to 9 in ten digits; 45 * 190
There are 100 times from 1 to 9 in 100 digits; 45 * 100
There are 1000 times of 1 in thousand digits;
All in all



There is a column of numbers 119999819971996, 11995. From three numbers, every number is before it
What is the difference between the large number and the decimal in the two numbers?


Did you miss a one between 1998 and 1997?



1*2/1+2*3/1+3*4/1+.98*99/1+99*100/1=?


Are you wrong? It should be: 1 / 1 * 2 + 1 / 2 * 3 + 1 / 3 * 4 +. 1 / 98 * 99 + 1 / 99 * 100, 1 / 1 * 2 + 1 / 2 * 3 + 1 / 3 * 4 +. 1 / 98 * 99 + 1 / 99 * 100 = (1 / 1-1 / 2) + (1 / 2-1 / 3) + (1 / 3-1 / 4) + +(1/98-1/99)+(1/99-1/100)=1/1-1/2+1/2-1/3+1/3-1/4+…… +1/98-1/99+1/...



99 / 1 + 99 / 2 + 99 / 3 +. 99 / 98


=99/(1+2+…… +98)
=99/2/[98×(98+1)]
=98/(2/98×99)
=2/98
=49



The radius of a circle is 6cm. What is the area of a sector with a central angle of 120 degrees


12pai
Area = (1 / 2) * arc length * radius
Arc length = radius * radian