How many square decimeters is the area of a rectangle made of two identical squares reduced by 20 centimeters in circumference

How many square decimeters is the area of a rectangle made of two identical squares reduced by 20 centimeters in circumference


2 square decimeters



Cut a square whose side length is a decimeter into two rectangles. How many square decimeters is the sum of the area of the two rectangles? The sum of the perimeter of the two rectangles?
Use the equation, please. Speed


The sum of area is still the square decimeter of A. the sum of perimeter is 4 * a + 2A = 6A



Which is the greater perimeter of a square or a rectangle of equal area


Rectangle



How to prove that the perimeter of a rectangle is greater than that of a square when the areas are equal


Let the length and width of the rectangle be a and B respectively, and the square be c
Then AB = C ^ 2
Because a is not equal to B
Then (√ a - √ b) ^ 2 > 0
a-2√ab+b>0
a+b>2√ab
Because C ^ 2 = AB, C = √ ab
Then a + b > 2C
2(a+b)>4c
Therefore, the circumference of a rectangle is larger than that of a square



The circumference of a rectangle is 26cm. If its length is reduced by 1cm and its width is increased by 2cm, it becomes a square. Let the length of the rectangle be xcm: equation


Let the length of the rectangle be xcm
(x+x-1-2)×2=26
2x-3=13
2x=16
x=8



The circumference of a rectangle is 26cm. If the length of the rectangle is reduced by 1cm and the width is increased by 2cm, it will become a square. If the length of the rectangle is xcm, the equation ()
A. x-1=(26-x)+2B. x-1=(13-x)+2C. x+1=(26-x)-2D. x+1=(13-x)-2


Let the length of the rectangle be xcm, then the width is (13-x) cm. According to the equivalent relation: the length of the rectangle - 1cm = the width of the rectangle + 2cm, the equation is: X-1 = (13-x) + 2, so choose B



The circumference of a rectangle is 26cm. If the length of the rectangle is reduced by 1cm and the width is increased by 2cm, it will become a square. If the length of the rectangle is xcm, the equation ()
A. x-1=(26-x)+2B. x-1=(13-x)+2C. x+1=(26-x)-2D. x+1=(13-x)-2


Let the length of the rectangle be xcm, then the width is (13-x) cm. According to the equivalent relation: the length of the rectangle - 1cm = the width of the rectangle + 2cm, the equation is: X-1 = (13-x) + 2, so choose B



A piece of square paper with a side length of 9 decimeters, divide it into 3 parts on average. How many square decimeters is the area of each paper? What is the perimeter of each small rectangle?


Area per unit = 9 * (9 / 3) = 27 square decimeters
Perimeter = 2 (9 + 9 / 3) = 24 decimeters



As shown in the figure, four identical small rectangles and one small square are inlaid into a square pattern. The known area of the pattern is 49, and the area of the small square is 4. If x and y are used to represent the length of the two sides of the small rectangle (x > y), please observe the pattern and write three equations represented by X and y


∵ the area of the pattern is 49, the area of the small square is 4, the side length of the pattern is 7, the side length of the small square is 2, the countable equation can be as follows: x + y = 7, x = y + 2, (x + y) 2 = 49, (x + y) 2 = (2Y + 2) 2, (x + y) 2 = 4xy + 4 (choose any three)



As shown in the figure is a combination of two rectangles, find the area of the combined figure, and turn the combined figure into two squares with the same area. Answer questions 1 and 2!
1) How much is the side length of a square?
2) When m = 10.18cm and N = 9.82cm, the area of the combined figure of two rectangles is calculated


1. The area of the combination of rectangles (3m + N + Mn) (M + N + m + 2n) + 2n × n, we get 8m & # 178; + 8N & # 178; + 16Mn, divide by 2, we get a square area (2m + 2n) &# 178;, so the side length is 2m + 2n
2. The area of rectangular combination is 4 (M + n) &# 178;, and the result is calculated by yourself. Some people say it is 1600