The perimeter of a rectangle is 72 meters. If its width increases by 1 / 4 and its length decreases by 1 / 8, and its perimeter remains the same as the original, what is the area of the rectangle?

Length · + width = 72 △ 2 = 36 (m)
Length + width = length (1-1 / 8) + width (1 + 1 / 4)
Length + width = 7 / 8 length + 5 / 4 width
1 / 8 length = 1 / 4 width
36 ÷ (8 + 4) = 3 (m)
Length: 3x8 = 24 (m)
Width: 3x4 = 12 (m)
Area: 12x24 = 288 (M2)

The perimeter of a rectangle is 88cm. If its width increases by 25% and its length decreases by one seventh, the area of the rectangle is calculated

[answer] 448 square centimeters
[analysis]

The perimeter of a rectangle is 64 meters. If the length is reduced by 1 / 10, the width is increased by 1 / 6, and the perimeter is unchanged, the area of the rectangle is calculated

Because the perimeter is constant, the length of 1 / 10 of the length is equal to the length of 1 / 6 of the width, and the length = (10 / 6) of the width;
Let the width be x and the length be (10 / 6) X
[x+(10/6)x]*2=64
(16/6)x=32
x=12
So the length is 12 * (10 / 6) = 20 meters
The area is 12 * 20 = 240 square meters

A rectangle is 64 meters in circumference. If the length is reduced by 1 / 10 and the width is increased by 1 / 6, the circumference remains unchanged. How to find the area of the original rectangle? (please give the formula)

1 / 6 of the width must be 1 / 10 of the length, so let one be X
10x+6x=64
16x=64
x=4
10 * 4 = 40. Sum of two lengths
6 * 4 = 24

If the length of a rectangle is reduced by 1 / 10, the width is increased by 1 / 6, and the perimeter is unchanged, the area of the original rectangle is calculated

2x+2y=64
2(9/10x+7/6y)=64
x+y=32
9/10x+7/6*(32-x)=32
x=15
y=32-x=17
s=x*y=15*17=255

After dividing a rectangle into three equal squares, the perimeter increases by 12 decimeters, and the area of each small square is ()

If the width of a rectangle is x, the length is 3x, and the side length of a square is X,
The circumference of the rectangle is 2 * 3x + 2 * x = 8x
The perimeter of the three squares is 3 * 4x = 12x
12x-8x=4x=12
x=3
The area of a small square is s = x ^ 2 = 3 ^ 2 = 9
The area is 9 square decimeters

After a square is divided into two rectangles, the perimeter increases by 36 decimeters. The original side length of the square is Decimeter, area is Square decimeter

36 △ 2 = 18 (decimeter); 18 × 18 = 324 (square decimeter); answer: the original side length of this square is 18 decimeters, the area is 324 square decimeters. So the answer is: 18324

The perimeter of the square is 36 decimeters. Divide the square into two rectangles of the same size. What is the area of a rectangle?

36 / 4 = 9 9 * 9 = 81 81 / 2 = 40.5 first find out the side length of the square, then find out the area of the square divided by two to find out the area of a rectangle

After a square is divided into two rectangles, the perimeter increases by 10 decimeters

Two more squares are added to make it longer, so the side length of the square is 10 △ 2 = 5DM
So area = 5 × 5 = 25dm & # 178;
Perimeter = 4 × 5 = 20dm

Divide a rectangle into three squares of the same size. The sum of the circumference of the three squares is 12 decimeters more than that of the original rectangle. How many decimeters is the circumference of the original rectangle?

Divide a rectangle into three squares of the same size, and the length of the original rectangle is three times the width
It needs to be cut twice to divide it into three squares. Each time, the width of two squares is increased by 2 * 2 = 4
So the width of the original rectangle is 12 △ 4 = 3 decimeters
The length is 3 × 3 = 9 decimeters
The circumference of the original rectangle is (9 + 3) × 2 = 24 decimeters

The perimeter of a rectangle is 72 meters. If its width increases by 1 / 4 and its length decreases by 1 / 8, and its perimeter remains the same as the original, what is the area of the rectangle?