Cut a piece of square paper with a side length of 36 cm into four identical small rectangular pieces. The sum of the circumference of the four small rectangular pieces is larger than that of the original square How many centimeters has the circumference increased?

Cut a piece of square paper with a side length of 36 cm into four identical small rectangular pieces. The sum of the circumference of the four small rectangular pieces is larger than that of the original square How many centimeters has the circumference increased?


You can draw a picture below
The original side length is 9cm and the perimeter is 36cm
It becomes four small rectangles, the long side of each rectangle is 9cm, and the short side is 9G4 = 2.25cm
The perimeter is (9 + 2.25) * 2 = 22.5cm
Because it is 4 small rectangles, so 22.5 * 4 = 90cm
90-36 = 54cm increased by 54cm
Let's take a look



If the perimeter of a square is 4cm, the perimeter of two squares is 6cm, the perimeter of a rectangle made of three squares is 8cm, the perimeter of a rectangle made of ten squares is 22cm, and the perimeter of a rectangle made of N squares is () cm


Square side length = square perimeter / 4 = 4 / 4 = 1cm
When a square is side by side, there are two sides between two adjacent blocks, so the perimeter will be less than two sides
Therefore, there are 4 x n - 2 x (n - 1) = 2 (n + 1) cm