Cut a square on the sheet iron of a right triangle (bottom 40, height 10). The area of the square is as large as possible. How about the area of the square?

Cut a square on the sheet iron of a right triangle (bottom 40, height 10). The area of the square is as large as possible. How about the area of the square?

Let the side length of a square be a, then the other side is (10-A) x (40 / 10)
So a = (10-A) x (40 / 10)
The solution is a = 8, so the area is 64

In a right triangle, one right side is 40, and the other right side is 10. Draw the largest square inside. What is the area of the square

As shown in the figure, in RT △ ACB, AC = 10, BC = 40, square mcnd is the largest square drawn in RT △ ACB. The key is to find the side length of the square. Let this side length be x, then MD = nd = XRT △ ACB area = AC × BC △ 2 = 10 × 40 △ 2 = 200rt △ ACB area

A right triangle, one right side is 40, the other right side is 10, draw the largest square in it, what's the area

Let the side length of the square be x, and we can find it by using the knowledge of similar triangles. X / (40-x) = 10 / 40, we can find x = 8, and the area is 8 * 8 = 64. If you draw a picture, it will be clear! Haha~~