Xiaohong and Xiaoqiang start from home at the same time. Xiaohong walks 52 meters per minute and Xiaoqiang 70 meters per minute. They meet at a on the way. If Xiaohong starts 4 minutes ahead of schedule and Xiaoqiang walks 90 meters per minute, they still meet at a. how many meters are Xiaohong and Xiaoqiang's homes apart?

Xiaohong and Xiaoqiang start from home at the same time. Xiaohong walks 52 meters per minute and Xiaoqiang 70 meters per minute. They meet at a on the way. If Xiaohong starts 4 minutes ahead of schedule and Xiaoqiang walks 90 meters per minute, they still meet at a. how many meters are Xiaohong and Xiaoqiang's homes apart?

Originally, the speed ratio of Xiaohong and Xiaoqiang was 52:70 = 26:35, then Xiaoqiang walked the whole course when they met: 35 ÷ (26 + 35) = 3561; later, the speed ratio of Xiaohong and Xiaoqiang was 52:90 = 26:45, when they met, Xiaoqiang also walked the whole course of 3561, then Xiaohong walked the whole course after Xiaoqiang started 3561 × 2645 × = 182549; the distance between Xiaohong's and Xiaoqiang's houses: (52 × 4) / (1-3561-182549) = 208 × 54952, = 2196 (m). A: the distance between Xiaohong's and Xiaoqiang's houses is 2196 M

This year, the sum of the ages of father and son is 88. When the age of father is the same as that of son this year, the age of father is exactly four times that of son. How old is the son this year?

Suppose your son is now x years old and your father is (88-x),
According to the conditions, when the father is also x years old, the distance is [(88-x) - x] years, that is, (88-2x) years, so the age of the son at that time should be [x - (88-2x)] years, that is, (3x-88) years
According to the conditions, the father's age is four times the son's age, that is, x = 4 * (3x-88), the solution is x = 32, so the son is 32 years old

Write the equivalent relation according to the meaning of the question,
For example, there are 40 apple trees twice as many as pear trees
Let x pear trees and Y apple trees be x + 40 = y
1. The actual power consumption is 38 degrees less than the plan
2. The number of boys is 1.2 times that of girls
3. The number of a is twice that of B by 20
1. The actual power consumption is 38 degrees less than the plan.
2. The number of boys is 1.2 times that of girls.
3. The number of a is twice that of B by 20

1. Set actual power consumption X and plan power consumption y
Then X-38 = y
2. There are x boys and y girls
x=1.2y
3. Let a be x and B be y
2x=y+20

Elementary school fifth grade application question, wants the equation, the equivalent relation formula, the solution to set
The girls in class 5 (1) made 283 lucky stars. If they made another 37, they would be twice as many as the boys. How many lucky stars did the boys in class 5 (1) make?

Set up five (1) class boys do X lucky stars
The number of male students is x2 times - 37 = 283
2x-37=283
2x-37+37=283+37
2x=320
x=160
A: the boys in class 5 (1) made 160 lucky stars