Olympic math problem urgent! 3. My grandfather is no more than 100 years old. My grandfather's age is five times that of my grandson. After a few years, my grandfather's age will be four times that of my grandson. After a few years, my grandfather's age will be three times that of my grandson. Now my grandfather's age is () years old (Updated) (to be added)

Olympic math problem urgent! 3. My grandfather is no more than 100 years old. My grandfather's age is five times that of my grandson. After a few years, my grandfather's age will be four times that of my grandson. After a few years, my grandfather's age will be three times that of my grandson. Now my grandfather's age is () years old (Updated) (to be added)

It's very simple. This topic starts with a hidden condition, that is, the age of grandfather and grandson and two years are natural numbers, that is, integers greater than 0
Let's set the grandson's age as X and the grandfather's age as 5x. Let's set the first years as a and the second years as B
Well, because grandfather's age is not more than 100, then 5x

An Olympic math problem
If 1 * 2 = 1 + 2, 2 * 3 = 2 + 3 + 4, 4 * 3 = 4 + 5 + 6, then 6 * 5 =?

The first number on the left side of the equation is the starting number, and the latter number is the number of additive numbers, and the additive number is 1 larger than the former one in turn, so
6*5=6+7+8+9+10

The value of the sixth power of (cube root π) is
 
 
The third power of 8 (x + 2) + 27 = 0
x=（）
 
 
Given that 3m-4 and 7-4m are the square roots of N, find the cube root of-2-n, where n = 100)
 

The value of the sixth power of - (- π ^ 2) 8 (x + 2) + 27 = 0 (x + 2) ^ 3 = - 27 = (- 3) ^ 3x + 2 = - 3x = (- 5) given that 3m-4 and 7-4m are the square roots of N, find the cube root of - 2-N, where n = 100); (3m-4) + (7-4m) = 0m = 3, then n (3m-4) ^ 2 = 25-2-n = - 27, cube root = - 3