Given m (4a-8, a + 3) in the plane rectangular coordinate system, the coordinates of point m are obtained according to the following conditions: (1) the distance between point m and X axis is 2. (2) the coordinate of point n is (3. - 6), and the line Mn ‖ X axis To be specific, every step should be taken. Good reward

Given m (4a-8, a + 3) in the plane rectangular coordinate system, the coordinates of point m are obtained according to the following conditions: (1) the distance between point m and X axis is 2. (2) the coordinate of point n is (3. - 6), and the line Mn ‖ X axis To be specific, every step should be taken. Good reward

(1) Because the distance from point m to X axis is 2
That is | y | = 2 = | a + 3|
The solution is a = - 1 or a = - 5,
Then the coordinates of point m are (- 12,2) or (- 28, - 2)
(2) Straight line Mn ‖ X axis,
Then the Y coordinates of M and N are equal
That is, a + 3 = - 6
a=-9
So the coordinates of point m are (- 44, - 6)

Given the point m (4a-8, a + 3) in the plane rectangular coordinate system, the coordinates of point m are obtained according to the following conditions:
(1) The distance from point m to the y-axis is 2
(2) The coordinates of point n are (3,6), and the line Mn / / X axis

The distance between M and Y is 2
So a + 3 = 2
A = - 1, so m (- 12.2)
(2) Straight line Mn / / X axis
A+3=6 A=3
So m (4,6)

Given that the coordinate of point m is (3-A, 4A + 8) and the distance between point m and two coordinate axes is equal, the coordinate of point m is calculated
There should be a specific process

The distance between M and the two axes is | 3-A | and | 4A + 8|
So | 3-A | = | 4A + 8|
3-A = 4A + 8 or 3-A = - (4a + 8)
a=-1,a=a=-11/3
So m (4,4) or (20 / 3, - 20 / 3)

Given that point m (4a-8,1-2a) is the integer point of the third quadrant, the coordinates of point m are obtained

4a-8