If point m (3a-9,40-2a) is in the second quadrant and the distance from point m to X axis is equal, try to find the coordinates of point M

If point m (3a-9,40-2a) is in the second quadrant and the distance from point m to X axis is equal, try to find the coordinates of point M

The topic is: if the point m (3a-9,40-2a) is in the second quadrant, and the distances from the point m to the X and Y axes are equal, try to find the coordinates of the point M
∵ point m (3a-9,40-2a) is in the second quadrant, and the distances from point m to x-axis and y-axis are equal,
∴|3a-9|=|40-2a|
-（3a-9）=40-2a
a=-31
3a-9=-102
40-2a=102
The coordinates of point m are (- 102102)

When a is the sum value, the points (x, y) that fit the conditions x + y = 2A + 1 and X-Y = 3a-2 are in the second quadrant (the points (x, y) in the second quadrant satisfy x < 0, Y > 0)

The solution of x = (5a-1) / 20 is a