If the point a (2m + 1,3-m) is symmetric about X axis in the fourth quadrant, then the value range of M is_______

If the point a (2m + 1,3-m) is symmetric about X axis in the fourth quadrant, then the value range of M is_______

So a is in the first quadrant
2m+1>0
3-m>0
-1/2

If the point m (a + 1, 2a-1) is in the fourth quadrant, then the value range of a is______ ．

∵ point m (a + 1, 2a-1) is in the fourth quadrant, ∵ a + 1 > 0, 2a-1 < 0. By solving the inequality, we get - 1 < a < 12, so the answer is - 1 < a < 12

Let X be the angle of three or four quadrants, and SiNx = 2a-3 / 4-A, then what is the value range of a?
The answer is a > 4 or a < - 1, but I only calculate a > 4. How can I calculate a < - 1?

∵ x is the angle of three or four quadrants
∴sinx∈[-1,0]
That is: - 1 ≤ 2a-3 / 4-A ≤ 0
The solution is a ≤ - 1 or a ≥ 4
∵4-a≠0
∴a＞4
A ＞ 4 or a ≤ - 1

If point m (3a-9, 10-2a) is in the second quadrant and the distance from point m to x-axis and y-axis is equal, try to find the value of (a + 2) 2008-1

∵ point m (3a-9, 10-2a) is in the second quadrant, and the distance from point m to x-axis and y-axis is equal, ∵ (3a-9) + (10-2a) = 0, the solution is a = - 1, ∵ (a + 2) 2008-1 = (- 1 + 2) 2008-1 = 1-1 = 0