Question 1: absolute value of - 2 / 7 - (- 1 / 2) + 2-1 and 1 / 2 question 2: 2 (x + 3) - 5 (1-x) = 3 (X-2) question 3: 1-x / 3-x-1 / 2 = 1 question 4

Question 1: absolute value of - 2 / 7 - (- 1 / 2) + 2-1 and 1 / 2 question 2: 2 (x + 3) - 5 (1-x) = 3 (X-2) question 3: 1-x / 3-x-1 / 2 = 1 question 4

The absolute value of - 2 / 7 - (- 1 / 2) + 2-1 and 1 / 2 = - 2 / 7 + 1 / 2 + 1 / 2 = 1-2 / 7 = 5 / 7, the second question: 2 (x + 3) - 5 (1-x) = 3 (X-2) 2x + 6-5 + 5x = 3x-67x-3x = - 6-14x = - 7x = - 7 / 4, the third question: 1-x / 3-x-1 / 2 = 1 2 (1-x) - 3 (x-1) = 62-2x-3x + 3 = 65x = 5-65x = - 1x = - 1 / 5

Given the square root of y = 2-x + the square root of X-2 + 7, find the square root of X + y

From the meaning of the title, we can know that: 2-x ≥ 0 and X-2 ≥ 0
The result is: X ≤ 2 and X ≥ 2
X can only be equal to 2
y=7
So the square root of X + y = (2 + 7) = 3