If 169m = a, 437n = 1a and 20 = 1, calculate the value of (36m + 74n-1) 2014

If 169m = a, 437n = 1a and 20 = 1, calculate the value of (36m + 74n-1) 2014

∵ 169m = a, 437n = 1a, ∵ 169m × 437n = 418m × 437m = 236m × 274n = 236m + 74n, = a · 1A = 1, ∵ 36m + 74n = 0, ∵ original formula = (- 1) 2014 = 1

The expansion of the square of X + MX + 8] [the square of X - 3x + n] does not contain the square of X and the cubic term of X, so we can find the value of M and n

Original formula = x ^ 4 + (M-3) x & # 179; + (n-3m + 8) x & # 178; + (mn-24) x + 8N
Without X & # 178; and X & # 179; the coefficient is 0
So M-3 = 0
n-3m+8=0
therefore
m=3
n=3m-8=1

If the fourth power of MX × (the K power of 4x) = - the 12th power of 12x, then the values of M and K are

The fourth power of MX × (the K power of 4x)
=The (K + 4) power of 4mx
=-The 12th power of 12x
So 4m = - 12, K + 4 = 12
m=-3,k=8

If - (MX to the fourth power) square * (4x to the K-2 power) = - 16x to the 10th power, then what are the suitable conditions for M and K

-Square of (MX to the fourth power) * (4x to the K-2 power) = - 16x to the 10th power
-m^2x^8*（4x^(k-2)）=-16x^10
-4m^2x^(k+6)=-16x^10
-4m^2=-16
M = 2 or M = - 2
k+6=10
k=4