The density of brick is 2.0 * 103kg / m3, the pressure that the foundation can bear is the quintic power of 8.82 * 10, and what is the maximum height of the wall?

The density of brick is 2.0 * 103kg / m3, the pressure that the foundation can bear is the quintic power of 8.82 * 10, and what is the maximum height of the wall?

Mathematical calculation
8.82*10^5/（2*10^3*9.8）=45m
In fact, if the wall is thickened, the foundation soil will be constrained, and the bearing capacity will be improved a lot
Just imagine, Mount Everest is a stone, 8844.43 meters, the pressure below will be very big, enough to crush any hard material, but, without crushing, it is due to the effect of three-dimensional constraints. Theoretically, under the same three-dimensional constraints, it is a plate of loose sand, and its bearing capacity is close to infinity

As shown in the figure, a bottle with a volume of 3 × 10-4m3 contains 0.2kg of water. A thirsty crow puts a small stone with a mass of 0.01kg into the bottle each time. When the crow puts 25 identical small stones into the bottle, the water surface rises to the mouth of the bottle, and then: (1) the total volume of stones in the bottle; (2) the density of stones

(1) The volume of 0.2kg water: V water = m water, ρ water = 0.2kg 1 × 103kg / m3 = 2 × 10-4m3; total volume of stone: V stone = V bottle - V water = 3 × 10-4m3-2 × 10-4m3 = 1 × 10-4m3; (2) density of stone: ρ stone = m stone, V stone = 0.01kg × 251 × 10 − 4m3 = 2.5 × 103kg / m3; answer: (1) total volume of stone in the bottle

A bottle with a volume of 3 × 10 - 4 cubic meters contains 200 grams of water
A bottle with a volume of 3 × 10 - 4 cubic meters contains 200 grams of water. A crow takes 25 identical pebbles with a quick mass of 10 grams each time, and the water surface rises to the mouth of the bottle to calculate (1) the total volume of pebbles in the bottle
(2) Total volume of stone

The volume of the stone is 100 cubic centimeters. (2) the density of the stone should be calculated. The density of the stone is 2.5 grams per cubic centimeter

As shown in the figure, a bottle with a volume of 3 × 10-4m3 contains 0.2kg of water. A thirsty crow puts a small stone with a mass of 0.01kg into the bottle each time. When the crow puts 25 identical small stones into the bottle, the water surface rises to the mouth of the bottle, and then: (1) the total volume of stones in the bottle; (2) the density of stones

(1) Volume of 0.2kg water: V water = m water, ρ water = 0.2kg 1 × 103kg / m3 = 2 × 10-4m3; total volume of stone: V stone = V bottle - V water = 3 × 10-4m3-2 × 10-4m3 = 1 × 10-4m3; (2) density of stone: ρ stone = m stone, V stone = 0.01kg × 251 × 10 − 4m3 = 2.5 × 103kg / m3; (1) total volume of stone in bottle is 1 × 10-4m3; (2) density of stone is 2.5 × 103kg / m3