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The weight of an object is 11n and its volume is 1 square decimeter. If it is immersed in water, what buoyancy does it suffer? If the density of the object is 1.2 × 10 000 kg / M The buoyancy received at rest is? N
Because the object is immersed in water, so f floating water = ρ water * V row * g = 1 * 10 ^ 3 kg / M & sup3; * 1 * 10 ^ - 3M & sup3; * 10N / kg = 10N if the object is immersed in salt water, then f floating salt 1 = ρ salt * V row * g = 1.2 * 10 ^ 3 kg / M & sup3; * * 1 * 10 ^ - 3 M & sup3; * 10N / kg = 12n > G, so f floating salt 2 = g object = 11n follows
The volume of an object is 100 square centimeters. What is the buoyancy of the object when it is immersed in water? (g = 10N / kg)
Immersion, then V row = V object = 100cm = 0.0001m buoyancy f floating = P water V row g = 1000kg / m * 0.0001m * 10N / kg = 1n
The volume of an object is 0.4 square decimeter. When it is completely immersed in water, what is its buoyancy? If the object is 4N, it will float up, sink and suspend in water (step)
Completely immersed in water, its buoyancy f = ρ water GV = 1000kg / m3 × 10N / kg × 0.0004m3 = 4N
If the weight of the substance is 4N, then f = g, it is suspended in water
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Put a metal with a mass of 250g and a volume of 300cm square into water, how much buoyancy is it when it is still? Help to solve
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What is the buoyancy of a metal with a mass of 250g and a volume of 300cm square when it is put into water at rest?
The volume should be 300 cubic centimeters
The average density of the metal ball is 250G / 300CM3 = 0.83g/cm3
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