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There is an object with a volume of 10 cubic decimeters and a weight of 70 n. put something into alcohol to calculate the buoyancy of the object when it is finally at rest [alcohol density = 0.8g/cm] There is an object with a volume of 10 cubic decimeters and a weight of 70 n. put something into alcohol to calculate the buoyancy of the object when it is finally at rest [alcohol density = 0.8g/cm]
1. The weight of this substance is 70N, so its mass is: M = g / g = 70 / 10 = 7kg (10 for G)
2. The density of this object: ρ = m / v = 7 / 10 = 0.7kg/dm ^ 3 = 0.7g/cm ^ 3
3. Alcohol density: ρ alcohol = 0.8g/cm ^ 3, so ρ substance < ρ alcohol, so the substance is floating on the alcohol
4. So the buoyancy of a stationary object is equal to its gravity: F = g = 70N
When a solid ball with a mass of 4.5kg and a volume of 5 cubic decimeters is put into water and alcohol respectively, what are the buoyancy forces on it at rest
The density of solid sphere is: ρ = m / v = 4.5kg/5 × 10 ^ - 3M & # 179; = 0.9 × 10 & # 179; kg / M & # 179;
∵ ρ ball ∵ ρ water
When a solid ball is floating in water, the buoyancy is equal to gravity
F = g = mg = 4.5kg × 9.8n/kg = 44.1n
∵ ρ ball ∵ ρ alcohol
The solid ball is at the bottom of the water
F = ρ alcohol g ∨ row = 0.8 × 10 ᦉ 179; kg / m ᦉ 179; × 9.8n/kg × 5 × 10 ^ - 3M ᦉ 179; = 39.2n
When an object is immersed in water and alcohol and let go, the buoyancy received in water is 6 N, while that in alcohol is 5 n
When an object is immersed in water and alcohol and let go, the buoyancy received in water is 6 N, while the buoyancy received in alcohol is 5 n
A. Floating in water and alcohol
B. Floating in water, sinking in alcohol
C. It floats in water and sinks in alcohol
D. Sink in water, float in alcohol
According to Archimedes's law, it is concluded that:
V drainage = f floating water / ρ water, g = 6N / 1000kg / m3 * 10N / kg = 6 * 10 ^ - 4m3;
V row alcohol = f floating alcohol / ρ alcohol g = 5N / 800kg / m3 * 10N / kg = 6.25 * 10 ^ - 4m3;
Because V drains
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