A solid iron ball with a volume of 100 cubic centimeters is immersed in water. What is the buoyancy of the iron ball? What is the direction of the force

A solid iron ball with a volume of 100 cubic centimeters is immersed in water. What is the buoyancy of the iron ball? What is the direction of the force

The solid iron ball with a volume of 100 cubic centimeter is immersed in water. The buoyancy of the iron ball is 1000 n, and the direction of the buoyancy is vertical upward

Put the ball weighing 4.9n and 300 cubic cm in water to find the final state of the ball and the buoyancy of the ball

Known: G ball = 4.9 n, V ball = 300 cubic cm = 3 * 10 ^ (- 4) m3, ρ iron = 7.8 * 10 ^ 3kg / m3
ρ water = 1 * 10 ^ 3kg / m3
Ask: the final state of the iron ball and its buoyancy F
First calculate the average density of the iron ball
The results show that ρ Ping = m ball / V ball = g ball / (g * V ball) = 4.9 / [9.8 * 3 * 10 ^ (- 4)] = 1.67 * 10 ^ 3kg / m3
Because ρ - level is greater than ρ - water, the ball is still when it sinks to the bottom
Then the buoyancy of the iron ball is f = ρ water * g * V ball = 1 * 10 ^ 3 * 10 * 3 * 10 ^ (- 4) = 3 n

A solid iron ball with a volume of 20 cubic centimeters is put into a sufficient amount of water. When it is still, how much buoyancy is it? When it is put into a sufficient amount of mercury, how much buoyancy is it

Put enough water, buoyancy = water density * iron ball volume * G
Put enough mercury (the iron ball floats on the mercury), buoyancy = the weight of the iron ball

Put the 50 cubic centimeter iron ball into the container full of water, and the overflow water weighs () Newton

M = P (water density) * V (iron ball volume). G = m * G