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The cylinder with a volume of 10 liters contains oxygen with a density of 1.5 times 10 Now use the piston to compress the volume of oxygen to 4 liters, what is the density of oxygen after compression
10 ∟ = 10 × 10 minus three cubic meters. Because the mass = density × volume, the mass = 10 × 10 minus three cubic meters × 1.5 times 10 cubic meters = 15 kg. Because the mass of oxygen before and after compression remains unchanged, and because the density = mass ／ volume = 15 ／ compressed volume = 15 ／ (4 × 10 minus three cubic meters) = 3.75 × 10 cubic meters, the density of compressed oxygen is 3.75 × 10 cubic meters
Solve (7 + 1) (7 square + 1) (7 third power + 1); (7 seventh power + 1) (7 eighth power + 1) =?
Original formula = (7 + 1) (7 ^ 2 + 1) (7 ^ 3 + 1). (7 ^ 7 + 1) (7 ^ 8 + 1)
=3102920229334694852718469120000
How much is the square of 7 + 7 + the third power of 7 +. 7 to the power of 2009?
Let s = 7 + 7 ^ 2 + 7 ^ 3 + +7^2009
Then 7S = 7 ^ 2 + 7 ^ 3 + 7 ^ 4 + +7^2009+7^2010
So 7s-s = 7 ^ 2010-7
S=(7^2010-7)/6
If the 9m power of 16 is a, the 37n power of 4 is one part of a, and the 0 power of 2 is one, the value of (36m + 74n-1) to the power of 2010 is obtained
It is known that 16 ^ 9m = a (1), and 4 ^ 37n = 1 / a (2); by substituting (1 * 2), we can get: 16 ^ 9m * 4 ^ 37n = 1, that is, 2 ^ 36m * 2 ^ 74n = 1, so 2 ^ (36m + 74n) = 1 = 2 ^ 0, so 36m + 74n = 0, we can get: original formula = (36m + 74n - 1) ^ 2010 = (0 - 1) ^ 2010 = (- 1) ^ 2010
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