What is the meaning of absolute value a + 5 on the number axis

What is the meaning of absolute value a + 5 on the number axis

The distance between a and 5

A B C has a number axis, as shown in the figure B ------ a -- 0 --- C reduction: the absolute value of a + B minus the absolute value of a-C plus the absolute value of B-C plus the absolute value of a-b

The absolute value of a + B minus the absolute value of a-C plus the absolute value of B-C plus the absolute value of A-B
=-(a+b)-(c-a)+(c-b)+(a-b)
=-a-b-c+a+c-b+a-b
=a-3b

If the real numbers a and B are opposite to each other on the number axis, what is the absolute value of a + B minus a?

a+b=0
2A + B equals a

When a is a real number and the absolute value of a is negative one, where should the corresponding point of a real number on the number axis be

The absolute value of a cannot be negative

A truck starts from the supermarket to deliver goods. First, it drives 30km south to unit a, then 20km south to unit B. after returning to the supermarket, it delivers goods to unit C 15km North for three times, and then returns to the supermarket for rest. (1) how far is unit C from unit a? (2) How many kilometers has the truck traveled?

Use a 4.5 unit length stick on the number axis to cover up to () integer points
A. 3B. 4C. 5D. 6

Use a 4.5 unit length stick on the number axis to cover up to 5 integer points

As shown in the figure, if there are six points on the number axis, and ab = BC = CD = de = EF, the integer closest to the number represented by point C is ()
A. -1B. 0C. 1D. 2

According to the numbers represented by a and F, AF = 11 + 5 = 16, ∵ AB = BC = CD = de = EF, ∵ EF = 16 △ 5 = 3.2, ∵ e, 11-3.2 = 7.8; C, 7.8 -- 3.2-3.2 = 1.4; the integer closest to the number represented by C is 1

A mathematical problem about the number axis, come in and have a look~
Given that there is a point P on the number axis, move the point one unit to the left for the first time, two units to the right for the second time, three units to the left for the third time and four units to the right for the fourth time·····
·After moving 100 times according to this rule, the number represented by the point on the number axis is_______ .
What is the law of the position relationship between the point and P after each movement?
What is the law of the distance from point P?
Which side of point P is it after moving 100 times? How far is it from point P?

P-1 + 2 - 3 + 4. - 99 + 100 = P + 1 + 1 + 1 (50 times in total) = P + 50
The odd motion is on the left, and the even motion is on the right,
Keep moving one unit twice away from point P,
Finally, 50 units away from P point on the right side

If a = - A, where is the point of a on the number axis?

A = - A, so 2A = 0, a = 0. So it means the origin of the point of a on the number axis

It is known that the digit 6 represented by point a on the number axis, B is a point on the number axis, and ab = 10
It is known that the digit 6 represented by point a on the number axis, B is a point on the number axis, and ab = 10. Starting from point a, the moving point P moves to the left at a speed of 6 unit lengths per second along the number axis at an average speed, and the movement time is t (T > 0) seconds
M is the midpoint of AP and N is the midpoint of Pb. Does the length of segment Mn change during the movement of point P? If it changes, please explain the reason; if it does not change, please draw a graph and find out the length of segment Mn
The picture is as follows
six
——·———·—————·——————
B 0 A
It's better to write a little simpler, graphics must be drawn!
The meaning of the figure above is not very clear. "6" represents the position of point a.

Unchanged
Suppose point P moves for 1 second, then AP is 6, BP is 4, the midpoint m of AP is 3 unit length away from point P3, and the midpoint n of BP is 5 unit length away from point P2
If point P moves for 0.5 seconds, then AP is 3, BP is 7, the midpoint m of AP is 1.5 unit length away from point P1, and the midpoint n of BP is 3.5 unit length away from point P3, so Mn is 5 unit length
Suppose that point P moves for 2 seconds, then AP is 12, BP is 2, the midpoint m of AP is 6 unit length away from point P, and the midpoint n of BP is 5 unit length away from point P1. (note that because point P has exceeded the range of AB, there is an overlapping part, which needs to be subtracted), so Mn is 5 unit length
If you don't understand the third hypothesis, you can see the following figure:
(the drawing of the building owner is wrong, please revise it)
P N B 0 (M) A
So, if point P moves for T seconds, then AP is 6T, BP is the absolute value of (10-6t), the midpoint m of AP is unit length away from point p3t, and the midpoint n of BP is unit length away from point P (5-3t), so Mn is 5-3t + 3T, that is, 5 unit length (note, here 5-3t is no longer an absolute value, that is, it can be a negative number)
What is not clear can be pointed out