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As shown in the figure, △ ABC, ∠ ACB = 90 °, CD ⊥ AB at point D, if ad = 6, BD = 2, then the length of BC is______ ．
In △ ABC, ∠ ACB = 90 ° CD ⊥ AB is at the point D ∪ BCD ∨ BAC ∪ ABC = bcbd ∪ BC2 = BD · AB = 2 × 8 = 16 ∪ BC = 4. The length of ∪ BC is 4
Please summarize your problem here. In the triangle ABC, the angle ACB is equal to 90 degrees, CD is the height of side AB, AC is equal to 15, BC is equal to 20, find the length of AD and BD
This is the first time that we want to ababababab178; (or = AC \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ + 15) (20-15) 25 (bd-ad) = 35 * 5
In the right triangle ABC, ∠ C = 90 °, BC = 8, triangle area = 24, find the height of hypotenuse ab
Because area = BC * AC / 2 = 24, so AC = 6
According to Pythagorean theorem, AB ^ 2 = AC ^ 2 + BC ^ 2
So AB = 10
Find the area of △ ABC in the right triangle ABC, ∠ C = 90 ° AB = 5, AC + BC = 6
AC + BC square = AC square + BC square + 2 * ac * BC
Because it is a right triangle ABC, AB square = AC square + BC square
AC + BC square = AB square + 2 * ac * BC
36=25+2*ac*bc
ac*bc=5.5
The area of △ ABC = 1 / 2 * ac * BC = 2.75
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