As shown in the figure, take the hypotenuse of the isosceles right triangle AOB as the right edge, make the second isosceles right triangle aba1 outward, and then use the isosceles right triangle a1bb1 Given OA = ob = 1, what is the area of the nth isosceles right triangle?

The area of the first 1 is 1 * 1 / 2 = 0.5
The second side length is 2 ^ 0.5, and the area is (2 ^ 0.5) * (2 ^ 0.5) / 2 = 1
At the same scale, the area of the nth is twice that of n-1, that is, the area of the nth is 0.5 * 2 ^ (n-1)

If the length of the hypotenuse of an isosceles right triangle is 4, the length of the waist of the triangle is 2
If the apex angle of isosceles △ ABC is 120 ° and the waist length is 10, the height of the base is ad=

Question 1: let the waist length be x, x square + x square = hypotenuse square, so the waist length is 4
Second question: if the bottom angle is 30 degrees, the height ad = 10 * sin30 degrees = 5

If the hypotenuse of an isosceles right triangle is radical 2, its area is

The hypotenuse of isosceles right triangle is root 2,
Then two right angle sides = 1
Its area = 1 * 1 / 2 = 1 / 2

How many hypotenuses does an isosceles right triangle always have?

It's root 2

If the hypotenuse of an isosceles right triangle is 10, the waist length is 10 The height on the hypotenuse is ．

∵ the hypotenuse of isosceles right triangle is 10, the waist length is 22 × 10 = 52, and the height on the hypotenuse is 10 × 12 = 5

If the square of the length of the hypotenuse of an isosceles right triangle is 8, then the waist length of the triangle is 8_ Which side is the hypotenuse?

The square of the waist + the square of the waist = the square of the length of the hypotenuse. 2 times the square of the waist = the square of the length of the hypotenuse
The solution is waist = 2

The waist of an isosceles right triangle is 4cm long and its area is (8) square cm. The hypotenuse of another isosceles right triangle is 4cm long and its area is?
If there is any mistake in the first question, please correct it. If there is no mistake in the second question, please teach me~`
Thank you~

Second question: right angle side = 4 / √ 2 = 2 √ 2cm;
Area = (1 / 2) * (2 √ 2) & # 178; = 4 square centimeter;

The formula for finding the length of an isosceles right triangle whose base length is 6cm
Isosceles right triangle: waist length = base length × √ 2 / 2
Waist length = 6 ×√ 2 / 2 = 3 √ 2 do you mean one waist length is three times root number two or the sum of two waists is three times root number two

This is very easy to calculate. You also gave the formula: waist length = 6 * root sign 2 / 2 = 3 times root sign 2. The sum of two waists is 6 times root sign 2
The waist length can also be calculated by calculating the area. Because it is an isosceles right triangle, the height is equal to half of the bottom, and the area is (3 * 6) / 2 = 9, that is, the square of the waist length is 18, and the waist length is root 18, which is three times root 2

Formula of side length of isosceles right triangle

Let both sides of the isosceles be a,
Then the proportion of the three sides is 1:1: √ 2

The length of the base of an isosceles right triangle is 6cm, so how high is it

Let the waist length be a, then the second power of 2 * a = 6 * 6, and a = 18
Let the height and length be B, then the quadratic power of (6 / 2) + the quadratic power of B = 18
B=3

As shown in the figure, take the hypotenuse of the isosceles right triangle AOB as the right edge, make the second isosceles right triangle aba1 outward, and then use the isosceles right triangle a1bb1 Given OA = ob = 1, what is the area of the nth isosceles right triangle?