If the acute angle between the heights of the two waists of an isosceles triangle is 70 degrees, what are the degrees of the three internal angles of an isosceles triangle?

If the acute angle between the heights of the two waists of an isosceles triangle is 70 degrees, what are the degrees of the three internal angles of an isosceles triangle?


If it is an acute triangle, the vertex angle is 70 and the base angle is 55; if it is an obtuse triangle, the vertex angle is 110 and the base angle is 35



If the acute angle between the lines of the heights of the two waists of an isosceles triangle is 70 degrees, then the degree of the vertex angle of an isosceles triangle is 70 degrees


(1) The acute angle between the heights of the two waists of an isosceles triangle is 70 degrees
If it is an obtuse triangle, the vertex angle is 110 degrees and the two base angles are (180-110) △ 2 = 35 degrees
110,35,35
(2) The acute angle between the heights of the two waists of an isosceles triangle is 70 degrees
If it is an acute triangle, the obtuse angle is 110 degrees, the apex angle is 70 degrees, and the two base angles are 110 △ 2 = 55 degrees
70,55,55



If the vertex angle of an isosceles triangle is 84 degrees, then the degree between the height of the waist and the bottom is ()


If the vertex angle of an isosceles triangle is 84 degrees, the degree between the height of a waist and the bottom is (42) °
Base angle = (180-84 °) / 2 = 48 degrees
Therefore, the degree between the height of a waist and the bottom is 180-90-48 = 42 degrees



If the vertex angle of an isosceles triangle is 84 degrees, then the degree of the angle formed by the height of a waist and the bottom is ()
A. 42°B. 60°C. 36°D. 46°


As shown in the figure: in △ ABC, ab = AC, BD is the height on the edge AC. ∵ a = 84 ° and ab = AC, ∵ ABC = ∵ C = (180 ° - 84 °) △ 2 = 48 °; in RT △ BDC, ∵ BDC = 90 °, ∵ C = 48 °; ∵ DBC = 90 ° - 48 ° = 42 °. So a



The angle between the height of a waist and the bottom of an isosceles triangle is α. The vertex angle of this isosceles triangle is ()
A. 2αB. αC. 12αD. 90°-α


As shown in the figure, in △ ABC, ab = AC, BD ⊥ AC is in D, ∠ DBC = α. Then ∠ BDC = 90 °, then ∠ C = ∠ ABC = 90 ° - α, so ∠ BAC = 180 ° - (∠ C + ∠ ABC) = 180 ° - 2 (90 ° - α) = 180 ° - 180 ° + 2 α = 2 α



The waist length and base of an isosceles triangle are 5:6, and the height of its base is √ 65. How to find the area and perimeter of the isosceles triangle


[area 195 / 4, perimeter 4 √ 65] this isosceles triangle has a waist length of 5:6 to the bottom, so the waist length of the isosceles triangle is 5:3 to the bottom, and the waist of the isosceles triangle is a right triangle with the half of the bottom and the height of the bottom. The waist is an oblique side, and the known height is √ 65



An angle of an isosceles triangle is 30 degrees Waist length is 16 cm. Find the triangle area
Calculate the top angle and bottom angle separately!


1) When the apex angle is 30 degrees, the height of a waist is 8 cm, and the triangle area is 16 × 8 △ 2 = 64 (square cm)
2) When the base angle is 30 degrees, the height of the base is 8 cm, the length of the base is 8 times root number 3, and the area of the triangle is 64 times root number 3 (square centimeter)



The perimeter of an isosceles triangle is 18 cm. If the median line of one waist divides the perimeter into two parts of 2:1, then the base length of the triangle is 18 cm
As the title


The base of the triangle is 10 cm long



If the height of the waist of an isosceles triangle is equal to half the length of one side of the triangle, what is the degree of the vertex angle of the triangle?


(1) The height of the waist is half the length of the waist
----->Vertex angle = 30 ° or 150 ° (in a right triangle, the side opposite 30 ° is half of the hypotenuse)
(2) The height of the waist is half the length of the bottom
--->Base angle = 30 ° top angle = 120



It is known that ad is the height of angle ABC, AB equals 25, ad equals 24, BC equals 14. It is proved that angle ABC is an isosceles triangle


"Ling Huanxin e":
Ad ⊥ BC, △ ABC are right triangles
AB²-AD²=BD²
25²-24²=625-576=49=BD²
BD=√49=7,
DC=BC-BD=14-7=7
BD=DC
△ADB≌△ADC(S.S.S)
| AB = AC (the corresponding sides of congruent triangles are equal)
Conclusion: ABC is an equilateral triangle
Good luck and goodbye