The girth of an isosceles triangle is 16cm, the height of its bottom is 4cm

Method 1: let the waist x base 16-2x bottom half 8-x Pythagorean theorem (8-x) ^ 2 + x ^ 2 = 4 ^ 2 get x = 5, so waist 5 base 6. Method 2: let the waist length of isosceles triangle a and the bottom edge be 2B, so 2A + 2B = 16cm -- A + B = 8. Because the height of the bottom edge is 4cm, so a ^ 2 = B ^ 2 + 16 substitute a = 8-b to get 64-16b + B ^ 2 = B ^ 2 + 1616b = 6

An isosceles triangle, the circumference is 49 cm, the ratio of the waist to the bottom is 2:3, how long is the bottom?

The ratio of the three sides is 2:2:3
The bottom length is 49 ÷ (2 + 2 + 3) × 3 = 49 ÷ 7 × 3 = 21cm

The length of the base of an isosceles triangle is 7cm. The median line on one waist divides the circumference of the triangle into two parts. If one part is 1cm longer than the other part, the waist length of the isosceles triangle is

Let the waist be X
be
1.X+1/2X=1/2X+7+1
The solution is: x = 8cm
2.X+1/2X+1=1/2X+7
The solution is: x = 6cm
The waist length of isosceles triangle is 8, or 6cm

The circumference of an isosceles triangle is 50cm and the bottom is 14cm. How long is its waist? A.36 b.22 c.18 d.11
Don't guess

The waist of an isosceles triangle is equal, that is to say, the remaining two sides are equal, so the total length of the remaining two sides is 50-14 = 36cm, so the waist length is 36 divided by 2 = 18cm

1. The circumference of an isosceles triangle is 18. If 3 times the waist length is 6 times more than 2 times the base, find a side length

Let the waist length be x and the bottom edge be y
There are
2X+Y=18...①
3X=2Y+6...②
From (1) and (2), x = 6, y = 6

The perimeter of isosceles triangle is 18.1) if the waist length is twice the base, calculate the length of each side. 2) if the length of one side is 8, calculate the length of other sides

(1) let the base length of the isosceles triangle be X
2x＋2x＋x＝18
5x＝18
x＝3.6
Waist length: 3.6 × 2 = 7.2
The three sides of the triangle are 7.2, 7.2 and 3.6
(2) the sum of the two sides of the triangle is greater than the third side, and the difference between the two sides is less than the third side
The isosceles triangle can only have a waist length of 8 and a base length of 2
The other sides are 8 and 2

In isosceles △ ABC, if the waist length is 8m and the bottom length is 4m, then the area of △ ABC is______ m2．

Let a be ad ⊥ BC over D, ∵ AB = AC, ∵ BD = DC = 12bc = 12 × 4m = 2m. In RT △ abd, according to Pythagorean theorem, ad = 82 − 22 = 215 (m), that is, the area of △ ABC is 12 × 4m × 215m = 415m2, so the answer is: 415

The waist length of an isosceles triangle is 5cm, and the area of △ ABC is 12cm square
It's faster than that

The problem is that the bottom edge is 6 and the height is 4
The solution steps are: set the height as X
So the base length is twice the square root of (5 ^ 2-x ^ 2)
Then multiply this result by X divided by 2 to get 12, and you can get the bottom length
The length of the bottom edge is 6

[Pythagorean theorem] it is known that if the waist length of an isosceles triangle is 10 and the upper height of one waist is 6, then the area of an equilateral triangle with the bottom as the side length is?

In the case of an acute triangle, the bottom is the root sign (36 + 4)
The square area is 40
If the obtuse angle triangle, the bottom is the root (36 + 18 * 18)
The square area is 360 square meters

The girth of an isosceles triangle is 16cm, the height of its bottom is 4cm