2lg(2x-1)=lg(-2x+7)+lg(x+1)

2lg(2x-1)=lg(-2x+7)+lg(x+1)

2lg(2x-1)=lg(-2x+7)+lg(x+1)
That is LG (2x-1) &# 178; = LG (- 2x + 7) (x + 1)
∴ (2x-1)²=(-2x+7)(x+1)
∴ 4x²-4x+1=-2x²+5x+7
∴ 6x²-9x-6=0
∴ 2x²-3x-2=0
∴ (x-2)(2x+1)=0
Ψ x = 2 or x = - 1 / 2
When x = - 1 / 2, 2x-1

LG (x + 6) - 1 / 2lg (2x-3) = 2-lg25 for X
I hope you can write the steps carefully,

lg(x+6)-1/2lg(2x-3)=2-lg25
lg(x+6)/(2x-3)^(1/2)=lg100/25=lg4
(x+6)/(2x-3)^(1/2)=4
x+6>0
2x-3>0
(x+6)=4(2x-3)^(1/2)
(x+6)^2=16(2x-3)
x^2+12x+36=32x-48
x^2-20x+84=0
(x-6)(x-14)=0
X = 6 or x = 14
Verify that x = 6 or x = 14 is the root of the equation

LG calculation thank you
Ac=20lg(Ad)
How much is AC = when ad = 2.5?

Ac=20 log(Ad)=20 log(2.5)=20[log (10/4)]=20[log10 - log4]=20[1-2log2]=20-40*log2...ans