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The circumference of an isosceles triangle is 32cm. The length of the waist is 3 times longer than that of the bottom, which is 6cm more than that of the bottom. Find the length of each side
Let the waist length be x and the bottom edge be y
2x+y=32
3x=2y+6
The solution is {x = 10, y = 12
The waist is 10 cm and the bottom is 12 cm
An isosceles triangle is divided into two triangles by the middle line of its waist. If the perimeter difference is 2 cm and the perimeter of an isosceles triangle is 18 cm, then its waist length is 2 cm___ ．
According to the meaning of the question, let the waist length be x and the bottom length be y. (1) when the waist is longer than the bottom length, the solution is: X-Y = 22x + y = 18, i.e. the waist length is 203cm; (2) when the bottom is longer than the waist length, the solution is: x-x = 22x + y = 18, i.e. the waist length is 163cm, i.e. x = 163y = 223, i.e. the waist length is 163cm
An isosceles triangle with a circumference of 21 cm is divided into two triangles by the middle line of a waist. If the difference between the two triangles is 3 cm, find the length of each side of the isosceles triangle
Let the waist length of an isosceles triangle be x cm and the base length be y cm. According to the meaning of the title, we get 2x + y = 21x − y = 3 or 2x + y = 21y − x = 3, and the solution is x = 8y = 5 or x = 6y = 9, ∵ 8 + 5 ＞ 8, 6 + 6 ＞ 9. The lengths of each side of the base length of the isosceles triangle are 8 cm, 8 cm, 5 cm or 6 cm, 6 cm and 9 cm respectively
The middle line on the waist of an isosceles triangle divides its circumference into two parts of 21cm and 15cm. Find the waist length of the isosceles triangle. Be careful and precise
Analyze the meaning of the question
The median line divides the circumference into two parts: one is waist plus half waist, and the other is half waist plus bottom
The median line divides its circumference into two parts: 21cm and 15cm, so the waist plus half waist equals 21 or 15
The waist can be set as X
Then x + X / 2 = 21 and x = 14;
X + X / 2 = 15 and x = 10
Given the midline of a waist of isosceles triangle, divide its circumference into two parts: 21cm and 15cm
When the waist length plus half of the waist length is 21, the waist length is 14 and the bottom length is 8. When the waist length plus half of the waist length is 15, the waist length is 10 and the bottom length is 16
The circumference of an isosceles triangle is 21cm. The middle line on one waist divides the isosceles triangle into two triangles with a circumference difference of 3cm. Find the length of each side of the isosceles triangle?
Two cases: the waist is 3 times longer than the bottom, and the bottom is 3 times longer than the waist
1、 Let the waist length be x, then the bottom length be x-3
∴2x+x-3=21
3x=24
x=8
Bottom length = 8-3 = 5
2、 Let the waist length be x, then the bottom length be x + 3
∴2x+x+3=21
3x=18
x=6
Bottom length = 6 + 3 = 9
After this kind of topic completes, must see, whether forms a triangle
An isosceles trapezoid has a waist length of 5 decimeters, a circumference of 24.5 decimeters and a height of 4.2 decimeters. What is its area?
Upper bottom + lower bottom = 24.5-5 × 2 = 14.5 decimeters
Area = 14.5 × 4.2 △ 2 = 30.45 square decimeter
Isosceles triangle with side length of 6 cm. Perimeter of 20 cm. How many cm is the other side length
The circumference of an isosceles triangle is 20 cm, and the length of one side is 6. Ask the other sides for help
If the side length is 6 is the bottom, then the two waist lengths are (20-6) △ 2 = 7. If the side length is 6 is the waist, then the bottom length is 20-6x2 = 8, so the other two sides are 7 and 7 or 6 and 8
One side of an isosceles triangle is 6cm long and its circumference is 20cm
(1) If 6cm is the base, then the waist length = (20-6) / 2 = 7cm (2). If 6cm is the waist length, then the base length = (20-6-6) = 8cm, the other waist length is 6cm, according to the sum of the two sides of the triangle is greater than the third side
RELATED INFORMATIONS
- 1. An isosceles triangle, one side is 30 cm long, the other side is 65 cm long, the triangle circumference is 30 cm
- 2. The circumference of an isosceles triangle is 160cm. The ratio of the waist length to the bottom length is 3:2. What is the waist length and the bottom length of this triangle
- 3. The ratio of the length of a waist to the length of the bottom of an isosceles triangle is 4:3. The circumference of the triangle is 528 cm. How many cm is the length of the bottom
- 4. An isosceles triangle, in which the length of two sides are 5 / 3 decimeter and 4 / 1 decimeter respectively, calculate the perimeter
- 5. It is known that the waist length of an isosceles triangle is 3 / 4 of the length of its base, and the length of one side is 11cm, then its circumference is_____________ .
- 6. If the vertex angle of an isosceles triangle is known to be 40 degrees, then the angle between the height of its waist and the bottom is 40 degrees______ ．
- 7. If the acute angle between the heights of the two waists of an isosceles triangle is 70 degrees, what are the degrees of the three internal angles of an isosceles triangle?
- 8. In ABC, ab = 7, AC = 5, BC = 3, find SINB, CoSb
- 9. It is known that △ ABC is an isosceles triangle, BD is high, and ∠ abd = 50 degrees It's a process
- 10. As shown in the figure, take the hypotenuse of the isosceles right triangle AOB as the right edge, make the second isosceles right triangle aba1 outward, and then use the isosceles right triangle a1bb1 Given OA = ob = 1, what is the area of the nth isosceles right triangle?
- 11. Be sure to see a reward. Pick up an isosceles triangle with a waist length of 10cm on a rectangular cardboard with a length of 17cm and a width of 16cm Very important, please answer with conscience! (one vertex of triangle and one vertex of rectangle are required to coincide, and the other two vertices are on the side length of rectangle). Please draw a figure or use words to show the detailed drawing process and find the method of drawing acute angle
- 12. It is known that the length of the base and the waist of an isosceles triangle are 6 and 5, respectively
- 13. The girth of an isosceles triangle is 16cm, the height of its bottom is 4cm
- 14. Let the length of one side of a triangle with an area of 12 square centimeters be a (?) and the height of this side be h (?). (1) find the analytic expression of the function of H with respect to a and the independent variable a Value range; (2) Is the function of H about a an inverse scale function? If so, please state its scale coefficient; (3) If the area of the triangle is changed to a fixed value s (square centimeter), and the rest is unchanged, find the analytic function of H with respect to a Solution
- 15. Draw a triangle with the largest area in a rectangle. The area ratio of the triangle to the rectangle is ()
- 16. Draw the largest triangle in the square. The area of the triangle is () of the area of the parallelogram
- 17. As shown in the figure, the rectangle efgh is connected to △ ABC, the bottom edge of △ ABC AC = B, the height BD = h, and the height eh = X. try to write out the functional relationship between the rectangle area s and X, and find out the value range of X
- 18. As shown in the figure, pdce is rectangular, ABCD is trapezoidal, plane pdce ⊥ plane ABCD, ∠ bad = ∠ ADC = 90 # 186;, ab = ad = # 189; CD = a, PD = √ 2 (1) If M is the midpoint of PA, the MDE of AC ‖ plane is proved; (2) Find the size of the sharp dihedral angle between planar pad and PBC
- 19. On the calculation of Newton's law 1. A truck with a mass of 50000kg runs along a smooth horizontal road at a speed of 0.3m/s, with a rope trailing behind it. If the tension of the rope is 250N, how long does it take to stop the truck? 2. There is a speed limit sign of 30km / h in a certain section. After the driver makes an emergency brake in this section, the inspector measures that the length of the brake trace is 12m. If the dynamic friction coefficient between the tire and the road is 0.6, ask the driver whether he has violated the speed limit specified in this section of the road. (hint: calculate the acceleration when braking from the braking friction, and then calculate the initial speed from the kinematic formula.)
- 20. 2lg(2x-1)=lg(-2x+7)+lg(x+1)