In a right triangle, the ratio of the degrees of the two acute angles is 1:8, and the difference between the two acute angles is 0___ Degree

90 ° / (1 + 8) × (8-1) = 10 ° × 7 = 70 °. Answer: the difference between the two acute angles is 70 °. So the answer is: 70

Given that the domain of definition of the function y = LG [(K + 2) x ^ 2 + (K + 2) x + 5 / 4] is r, find the value range of K
(k+2)x^2+(k+2)x+5/4>0
Because the domain of definition is all real numbers, the discriminant is used
△=b^2-4ac

Because if △ energy = 0, the polynomial will have an intersection with the x-axis (only one). If there is an intersection, the function at the intersection is meaningless
Because the polynomial must be greater than 0
The solution is - 2 < K < 3, but there is another case,
When k = - 2, y = lg5 / 4 is meaningful, and the definition field of X is r
So the solution of K is - 2 ≤ K < 3

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In a right triangle, the ratio of the degrees of the two acute angles is 1:8, and the difference between the two acute angles is 0___ Degree