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Find the domain of the following function: y = LG (2sinx-1)
A:
The domain of the function y = LG (2sinx-1) satisfies:
2sinx-1>0
sinx>1/2
So:
2kπ+π/6
The domain of the function y = LG (1-2sinx) is ()
1-radical 2sinx > 0;
→ root 2sinx
The domain of the function f (x) = LG (2sinx-1) is
2sinx-1>0
sinx>1/2
From the sine curve: π / 6 + 2K π
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