As shown in the figure, in △ ABC, ab = AC, D is a point on the edge of BC, with AB and BD as adjacent sides, make parallelogram ABDE and connect AD and EC

As shown in the figure, in △ ABC, ab = AC, D is a point on the edge of BC, with AB and BD as adjacent sides, make parallelogram ABDE and connect AD and EC


It is proved that: ∵ AB = AC, ∵ ABC = ACB, ∵ quadrilateral ABDE is parallelogram, ∵ ab ∥ De, ab = De, ∵ ABC = EDC, ∵ ACD = EDC, ∵ AB = AC, ab = De, ≌ AC = de. in △ ADC and △ ECD, AC = De, ACD = edccd = DC, ≌ ADC ≌ ECD (SAS)



As shown in the figure, △ ABC, ab = AC, extend BC to D, make CD = BC, point E on edge AC, make ▱ cdfe with CE and CD as the adjacent edge, cross point C as CG ∥ AB with point G, connect BG, de. (1) ∠ ACB and ∠ GCD. What is the quantitative relationship? (2) verification: △ BCG ≌ △ DCE


(1) The reasons are as follows: ∵ AB = AC, ∵ ABC = ∵ ACB ∵ CG ∥ AB, ∵ ABC = ∵ GCD, ∵ ACB = ∵ GCD. (2) it is proved that ∵ quadrilateral cdfe is a parallelogram, ∥ EF ∥ CD.