Given that the image of quadratic function y = 2x square + BX + C passes through point a (2,3) and intersects with line y = 3x-2 at point B (1, m), the relation of quadratic function is obtained

Given that the image of quadratic function y = 2x square + BX + C passes through point a (2,3) and intersects with line y = 3x-2 at point B (1, m), the relation of quadratic function is obtained


Point B is brought into the straight line to get (1,1),
Bring in a and B, and you'll have to
8+2b+c=0
2 + B + C = 0, B = - 6, C = 4
So the quadratic function is y = 2x square - 6x + 4



y=-0.25x^2+5x
When the quadratic function of one variable is the maximum, we can find the value of X~


Can we calculate the derivative? If we can't find the formula: - 0.25 (xx-20x) = - 0.25 (X-10) square + 25, then x = 10