(3x-4)^2=9X-12

(3x-4)^2=9X-12


(3x-4)^2=9X-12=3(3x-4)
(3x-4)(3x-4-3)=3x(3x-1)=0
So x = 1 / 3 or 3x-4 = 0, x = 4 / 3



Solution equation: 1 − 3x1 + 3x + 3x + 13X − 1 = 121 − 9x2


If both sides of the equation are multiplied by (1 + 3x) (1-3x), we can get: (1-3x) 2 - (1 + 3x) 2 = 12, and the solution is x = - 1. Test: when x = - 1, (1 + 3x) (1-3x) ≠ 0  x = - 1 is the solution of the original equation