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(3x-4)^2=9X-12=3(3x-4) (3x-4)(3x-4-3)=3x(3x-1)=0 所以x=1/3或3x-4=0 x=4/3
方程兩邊都乘(1+3x)(1-3x),得:(1-3x)2-(1+3x)2=12,解得x=-1.檢驗:當x=-1時,(1+3x)(1-3x)≠0∴x=-1是原方程的解.
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