It is known that the maximum value of quadratic function is 8, and its image passes through (- 2,0) and (1,6)

It is known that the maximum value of quadratic function is 8, and its image passes through (- 2,0) and (1,6)

Its image passes (- 2,0) and (1,6) two points (- 2,0) and (1,6) points, to get 4a-2b + C = 0, a-2b + C = 0, ① a + B + B + C = 6, ② + 2 + 2, 4a-2b + C + 2A + 2A + 2B + 2B + 2B + 2B + 2B + 2B + 2B + 2C = 12 formula = y = ax + BX + BX + C, its image passes (- 2,0) and (1,6) two points (- 2,2,0) and (1,2,2,2,2,2,2,2,2,2,2,4a-2b-2b-2b) and (4a (4ac-b) / 4A = 8, the maximum value of the quadratic function is 8, 8, the maximum value of the quadratic function is 8, 8, the maximum value is 8, the largest value of 8, 8, the largest value of the maximum of the quadratic function is 8, 8, the maximum is 8, the largest value of 8, the in addition, B2 = 16 / 9, C2 = 40 / 9, so the analytic expression of the function is y = - 2x + 8 or y = - 2 / 9x + 16 / 9x + 40 / 9

Given the quadratic function image through (1,0); (2,0); (0,2), find its expression

y=ax^2+bx+c
After (1,0); (2,0); (0,2)
0 = a+b+c
0=4a+2b+c
2=0+0+c
a=1,b=-3,c=2
y = x^2-3x+2