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The coordinates of vertex a, B, D of parallelogram ABCD are a (0,0), B (2,2), D (4, - 3), respectively. Find the coordinates of point C and the area of parallelogram ABCD
There's not enough units, there's no solution~
It is known that the coordinates of the three vertices of △ ABC are a (- 3, - 1), B (1,3) and C (2, - 3) (1) describe each point in the plane rectangular coordinate system and draw △ ABC; (2) calculate the area of △ ABC
(1) The area of △ ABC = 5 × 6-12 × 4-12 × 2 × 5-12 × 1 × 6 = 30-8-5-3 = 30-16 = 14
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