Take a (0,0), B (4,0) C (2,3) as the vertex to draw a parallelogram and the coordinates of the fourth vertex D of the ball

Take a (0,0), B (4,0) C (2,3) as the vertex to draw a parallelogram and the coordinates of the fourth vertex D of the ball


Three possibilities,
1, take AB side as diagonal, then d (6,3)
2, taking AC side as diagonal, then d (- 2,3)
3, taking BC side as diagonal, then d (2, - 3)



As shown in the figure, ABC is the three vertices of a parallelogram, and the coordinates of ABC are (3,4) (7,1) (5,5). Draw a parallelogram in the figure and write the coordinates of its fourth vertex directly


If it's not easy to draw, it's unnecessary
We'll find the fourth point (x, y)
If AB is diagonal, then 3 + 7 = 5 + X, 4 + 1 = 5 + y (5,0)
If AC is diagonal, then 3 + 5 = 7 + X, 4 + 5 = 1 + y (1,8)
If BC is diagonal, then 7 + 5 = 3 + X, 1 + 5 = 4 + y (9,2)



Given the points a (2,0), B (- 12,0) and C (0,1), draw a parallelogram with three points a, B and C as the vertices. Then the fourth vertex cannot be in ()
A. First quadrant B. second quadrant C. third quadrant D. fourth quadrant


According to the properties of the edges of a parallelogram, the opposite edges are equal. We can know that the coordinates of another vertex can be: (112, - 1) or (212,1) or (- 212,1).. it is not in the third quadrant. So we choose C