First simplify, then evaluate: 1 - [(x) - 1 / 1-x] 2 divided by x2-x + 1 / x2-2x + 1, where x2-x + 5 = 0

First simplify, then evaluate: 1 - [(x) - 1 / 1-x] 2 divided by x2-x + 1 / x2-2x + 1, where x2-x + 5 = 0

The original formula = 1 - [(x) - 1 / (1-x)] and # 178; △ [(X & # 178; - x + 1) / (X & # 178; - 2x + 1)]
=1-[x(1-x)/(1-x)-1/(1-x)]²÷[(x²-x+1)/(x-1)²]
=1-[(x-x²-1)/(1-x)]²×[(x-1)²/(x²-x+1)]
=1-[(x²-x+1)/(x-1)]²×[(x-1)²/(x²-x+1)]
=1-[(x²-x+1)²/(x-1)²]×[(x-1)²/(x²-x+1)]
=1-(x²-x+1)
=-(x²-x)
∵ x²-x+5=0
∴ x²-x=-5
Original = - (- 5)
=5

Evaluation: 3x-4x ^ 2 + 7-3x + 2x ^ 2 + 1, where x = 2

3x-4x^2+7-3x+2x^2+1
=-2x²+8
When x = 2, the original formula = - 2x & # 178; + 8 = - 2 * 2 & # 178; + 8 = 0

Calculation: (1) x + 2Y + (4Y ^ 2 / x-2y) (2) (x / x ^ 2-1) divided by (x ^ 2 + 4x + 3) / (x ^ 2 + 2x + 1) (3) 12 / (m ^ 2-9) plus 2 / (3-m) M
Question 3 m is not equal to plus or minus 3
X + 2Y + 4Y ^ 2 / (x-2y)

Is your small bracket ambiguous? Question 1 x-2y is a whole on the denominator? Question 2 x ^ 2-1 is a whole on the denominator? Question 3 = 12m / ((M-3) (M + 3) m) - 2 (M + 3) / ((M + 3) (M-3) m) = (6m-6) / ((M + 3) (M-3) M

The following four groups of deformations belong to the term shifting deformation: (a) from X-2 = 12 of 4 X-2 = 3, (b) from 2x = 3 to x = 3 of 2, (c) from 4x = 2x-1 to 4x-2x = - 1
D 3Y - (Y-2) = 3, then 3y-y + 2 = 3

The following four groups of deformations belong to term shifting deformation are (c)

How to calculate 2x + 0.6 = 3.6

2x+0.6=3.6
2x=3.6-0.6
2x=3
x=1.5

How about 75x-3% 2x = 6% 1?

The original title is equal to:
3/4x-2/3x=1/6
(9/12-8/12)x=1/6
1/12x=1/6
x=2

How to calculate 5 / 2-x > 3 / 3-2x + 1?

Multiply both sides by six
3*（5-x）＞2*（3-2x+1）
15-3x＞6-4x+2
x＞-7

How to calculate (2x / 5 + 14) times 1 / 3 = x - (2x / 5 + 14)? Answer in 10 minutes

(2x / 5 + 14) times 1 / 3 = x - (2x / 5 + 14)
2X of 15 + 14 of 3 = 2x-14 of X-5
2x-x of 15 + 2x of 5 = - 14-14 of 3
-7x of 15 = - 56 of 3
X = (- 56 / 3) × (- 15 / 7)
x=40

How to calculate X-1 of 2 = 2x of 5

X-1 of 2 = 2x of 5
Multiply 10 to get 5 (x-1) = 4x
5x-5=4x
5x-4x=5
x=5

|How to calculate X-5 | + | 2x-3 | (1 | x | 5), we need to be a little hip

Because: 1 < x < 5
So: | X-5 | = 5-x | 2x-3 | = 2x-3
That is, | X-5 | + | 2x-3|
=5-x+2x-3
=2+x