What is the quotient of 0.4 times 5 divided by 2.5?

What is the quotient of 0.4 times 5 divided by 2.5?

0.4×(5÷2.5)
=0.4×2
=0.8

What is the quotient of the product divided by 4.5?

4.5÷[(8.6－6.2)×1.5]
=4.5÷[2.4×1.5]
=4.5÷3.6
=1.25

If f (x) = asin (TTX + a) + bcos (TTX + β), where a, B, α and β are non-zero real numbers and f (2010) = 2, then f (2011)=

-2

F (x) = asin (π x + a) + bcos (π x + b), and f (2009) = 3, find f (2010)

f(2009)=asin(2009π+a)+bcos(2009π+b)
f(2010)=asin(2010π+a)+bcos(2010π+b)
=asin(π+2009π+a)+bcos(π+2009π+b)
=-[asin(2009π+a)+bcos(2009π+b)]
=-f(2009)
=-3

Let f (1) = a, f (x) = asin (π x + α) + bcos (π x + α), where ab α ∈ R and a B ≠ 0, α ≠ K π (K ∈ z) if f (2009) = 5, find f (2010)

f(x)=asin(πx+α)+bcos(πx+α)
f(1)=asin(π+α)+bcos(π+α)=-（asinα+bcosα）=a
f(2009)=asin(2009π+α)+bcos(2009π+α))=asin(π+α)+bcos(π+α)
=-（asinα+bcosα）=a=5
f(2010)=asin(2010π+α)+bcos(2010π+α)=asinα+bcosα=-a=-5

Given the function f (x) = asin ω x + bcos ω X. given the function f (x) = asin ω x + bcos ω x... Then the value range of M of the maximum value of F (x) is
Given the function f (x) = asin ω x + bcos ω x (where ω > 0, a and B are not all zero), given the function f (x) = asin ω x + bcos ω x... Then the value range of M of the maximum value of F (x) is
A. M > = radical 3
B. 0 〈 m 〈 = radical 3
C. M > radical 6
D.0
Minimum positive period = 2
Forget there's another condition

Given the function f (x) = asin (π x + α) + bcos (π x + β) + 1, and f (2006) = - 1, what is the value of F (2007)?

f（2007）=asin(π2007+a)+bcos(2007π+b)+1
=asin(2006π+a+π)+bcos(2006π+b+π)+1
=-asin(2006π+a)-bcos(2006π+b)+1
According to sin (x + π) = - SiNx;
Because f (2006) = - 1
So asin (2006 π + a) + bcos (2006 π + b) = - 2;
So the original formula = 3

Given the function f (x) = asin (π x + a) + bcos (π x + β), and f (2011) = 3, then what is the value of F (2012), it is better to have a detailed solution for each step

Because: F (x) = asin (π x + a) + bcos (π x + β), and f (2011) = 3, so: F (2011) = asin (2011 π + a) + bcos (2011 π + β) = 3 according to the induction formula, there are: - Asina bcos β = 3 (formula 1) f (2012) = asin (2012 π + a) + bcos (2012 π + β) = Asina + bcos β (formula 2) (formula 1) + (formula 2

Given the function f (x) = asin (π x + a) + bcos (π x + β), and f (2011) =; 2, what is the value of F (2012),

2012 is divided into 2011 and more than 1, which is simplified by the formula (sin (a л) = - Sina; cos (a л) = - COSA), and the final result is - 2

Given the set a = {1,3, m} set B = {m ^ 2,1} and a ∪ B = a, find the value of M

B is a subset of A
M & # 178; = m or 3
m²=m
Because the set elements are different
m≠1
m=0
m²=3
So m = - √ 3, M = √ 3, M = 0