Two fifths of the number a is less than one-half of the number B by 5. Given that the number B is 20, find the number a
Let a be X
1/2*20-2/5x=5
The solution is x = 12.5
3.2 × 0.25 × 0.125 (simple calculation)
3.2×0.25×0.125
=0.4×0.25×8×0.125
=0.1×1
=0.1
3.2 × 0.25 × 0.125 (simple calculation) (writing process)
3.2×0.25×0.125
=0.4×0.25×8×0.125
=0.1×1
=0.1
25 + 125 * 3.2 simple operation
25+125*3+125*0.2=25+375+25=425
I don't know if it's easy enough
Simple calculation: [5-3 and 7 / 8 ÷ (1 and 5 / 6 + 2.25 × 1 / 3)] 0.125
[5-3 + 7 / 8 (1 + 5 / 6 + 2.25 × 1 / 3)] 0.125
=[5-3 and 7 / 8 △ (11 / 6 + 9 / 4 × 1 / 3)] 1 / 8
=【5-31/8÷(11/6+9/4×1/3)】×8
=【5-31/8÷(11/6+3/4)】×8
=【5-31/8÷(31/12)】×8
=【5-3/2】×8
=40-12
=28
39.7 × 2.8 + 3.97 × 72
39.7×2.8+3.97×72
=3.97×10×2.8+3.97×72
=3.97×28+3.97×72
=3.97×(28+72)
=3.97×100
=397
How to calculate 72 × 39 + 72 simply?
Use the ladder equation!
72×39+72
=72x(39+1)
=72x40
=2880
Simple calculation of 39 * 8 + 6 * 39-39-4
39*8+6*39-39-4
=39×(8+6-1)-4
=39×13-4
=503
How to use recursive equation to calculate 45 times 45 + 55 times 45
55 times 45 minus 45 times 45 simple calculation with recursive equation