1.75 * 7:6 + 14:3 * 1 and 4:3 + 1 and 4:3 Recursive equation calculation,

1.75 * 7:6 + 14:3 * 1 and 4:3 + 1 and 4:3 Recursive equation calculation,

1.75 * 7:6 + 14:3 * 1 and 4:3 + 1 and 4:3
=1:3 * 7:6 + 14:3 * 1:3 + 1:3
=1 and 3 / 4 (6 / 7 + 3 / 14 + 1)
=7 / 4 × (12 / 14 + 3 / 14 + 14 / 14)
=7 / 4 × 29 / 14
=29 out of 8

(4x+2)/x+(4x-22)/(x-5)=(x-6)/(x-4)+(7x+9)/(x+1)

(4X+2)/X+【4(X-5)-2】/(X-5)=【(X-4)-2】/(X-4)+【7(X+1)+2】/(X+1)
4+2/X+4-2/(X-5)=1-2/(X-4)+7+2/(X+1)
8+2/X-2/(X-5)=8+2/(X+1) -2/(X-4)
2/X-2/(X+1)= 2/(X-5) -2/(X-4)
1/X-1/(X+1)=1/(X-5)-1/(X-4)
1/【X(X+1)】=1/【(X-5)(X-4)】
20-10X=0
X=2

It is known that if the cubic polynomial of X is divided by X & # 178; - 1, the remainder is 4x + 4. If it is divided by X & # 178; - 4, the remainder is 7x + 13
Find the cubic polynomial and factorize it

Let the quotient of the polynomial divided by x ^ 2-1 be ax + B [∵ the polynomial is cubic, and the quotient can only be once after it is divided by quadratic]; the quotient of the polynomial divided by x ^ 2-4 is CX + D
Then (x ^ 2-4) (Cx + D) + 7x + 13 = (AX + b) (x ^ 2-1) + 4x + 4
=> cx^3-4cx+dx^2-4d+7x+13=ax^3+bx^2-ax-b+4x+4
=> cx^3+dx^2+(7-4c)x+(13-4d) =ax^3+bx^2+(4-a)x+(4-b)
=> c=a ； d=b；7-4c=4-a ；13-4d=4-b
=> a=c=1 ,b=d=3
Therefore, the cubic polynomial is factorized as x ^ 3 + 3x ^ 2 + 3x + 1, and the original formula = (x + 1) ^ 3

4 equals? Simple operation

＝2/5×1/10 +9/10×2/5＝2/5×（1/10+9/10）＝2/5×1＝2/5